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Enter The Range Of Values For X

Posted by Serambi Pengetahuan on Kamis, 01 Juni 2023


Enter The Range Of Values For X

Determine the range of values for which the following inequalities are true c. 3x + 5 ≥ 2x-4

Daftar Isi

1. Determine the range of values for which the following inequalities are true c. 3x + 5 ≥ 2x-4


3x + 5 ≥ 2x - 4
3x - 2x ≥ -4 -5
x ≥ -9

semoga membantu.....

2. Find the value of 1/2 for given values of x​


Jawaban:

tidak tau jajajamkslsos0soakkanabjaidjd

Penjelasan dengan langkah-langkah:

shdjsjsksklalapqlm2oe8urndjkslapa0papa


3. The range of values of x + 1 < 14 and 2x + 3 > 11 is...​


Jawaban:

4<x<11 or (4, 11)

Penjelasan dengan langkah-langkah:

x+1 < 14

x < 14 - 1

x < 13

2x + 3 > 11

2x > 8

x > 8/2

x > 4

so, the solution is

4<x<13

or another writing

(4, 13)

Jawab:

{5, 6, 7, 8, 9, 10, 11, 12}

Penjelasan dengan langkah-langkah:

x + 1 < 14

= x < 13 (x is smaller than 13)

&

2x + 3 > 11

= 2x > 8

= x > 4 (x is bigger than 4)

Then we can say that x is bigger than 4 and smaller than 3, therefore we can simplify it as the inequality below:

4 < x < 13

And the range of possible values of x will be {5, 6, 7, 8, 9, 10, 11, 12}

Hope this helps :D


4. determine the range of values for which the following inequalities are true: a. x + 2 > 10 b. x < 2x - 12 c. 3x + 5 greater than or aqual to 2x - 4


a. x > 10-2
x > 8
b. x-2x < -12
-x < 12
x < 12

5. The expression (


Jawaban:

Daily Expression in English

Sorry, I didn't mean to. Maaf, saya tidak sengaja.

You are really something. Kamu ada-ada saja.

Take it easy. Santai saja.

Don't block my sight. Jangan halangi pandanganku.

I change my mind. Saya berubah pikiran.

Don't give up! Jangan menyerah!

I don't care. Saya tidak peduli.

Please move a bit. Tolong geser sedikit.


6. Find the values of the unknown. Wayss


Jawaban:

x 27,5°

y 10°

Penjelasan dengan langkah-langkah:

tengkyuu ngabbb


7. Establish a table of values for f(x)=5x³-8x²+10 for -1.5 ≤ x ≤ 2, including half values of x. Key in your answer a list of ordered pairs, starting from the least value of x​


Jawab

Penjelasan dengan langkah-langkah:

250x


8. If (ax + 2)(bx + 7) = 15x2 + 2x + 14 for all values ofx, and a + b = 8, what are the two possiblevalues for c ?​


Penjelasan dengan langkah-langkah:

First we can expand the left hand side:

(ax+2)(bx+7)abx2+2bx+7ax+14abx2+(7a+2b)x+14=15x2+cx+14=15x2+cx+14=15x2+cx+14

We can equate coefficients to see that

ab7a+2b=15=c(x2)(x)

We can say that

a+ba=8=8−b

And thus

ab(8−b)b8b−b2b2−8b+15(b−5)(b−3)=15=15=15=0=0

So we can say b=3 or b=5

When b=3, then a=5 and we can say that

c=7a+2b=7×5+2×3=35+6=41

When b=5, then a=3 and we can say that

c=7a+2b=7×3+2×5=21+10=31

So, the two values of c are 41 and 31


9. Given that 5x² - 7x + 3 = A(x - 1)(x - 2) + B(x - 1) + C for all values of x, find the values of A, B, and C!


Penjelasan dengan langkah-langkah:

5x²-7x+3= A(x²-3x+3)+BX-B+C

5x²-7x+3= Ax²-3Ax+Bx+3A-B+C

maka A = 5

maka 3A-B= 7

3(5)-B= 7

B= 8

maka 3A-B+C= 3

= 15-8+C= 3

maka C= -4

maka (A,B,C)---> (5,8,-4)✓


10. By completing the square, prove that 2x^2-4x+3=0 is always positive for all real values of x​


Jawab:

fungsi kuadrat selalu bernilai positif jika :

a> 0 dan D < 0

f(x) = 2x²-4x+3

a = 2  --> 2 > 0 ,  sehingga terbukti a > 0

D = b² - 4 ac

  = (-4)² - 4(2)(3)

  = 16 - 24

  = -8 -----> -8 < 0, sehingga terbukti D < 0


11. The quadratic equation ( 1 + k) xkuadrat 4kx + 9 = 0 has two distinct real number roots. The range of values of k is....


syarat memuliki 2 akar real yang berbeda adalah D > 0
D = b² - 4ac

(1 +k)x² + 4kx + 9
D > 0
(4k)² - 4(1+k)(9) > 0
16k² - 36 - 36 k > 0
4k² - 9k - 9 > 0
(4k + 3)(k - 3) > 0
k = -3/4 ATAU k = 3

_+__|__-__|__+__
     -3/4        3
karena kurang dari, maka daerah yang negatif jawabannya -3/4 < x < 3

Maaf kalau salah^^


12. Which the following function is always positive for all values of x?


bagaimana mengikuti selalu positif dengan semua

13. fine the values of x and y the satisfy the eqution ( x+y) + (x-y) = 14.8 + j6.2


2x = 14.8 + 6.2
2x = 21
x = 21/2
x = 10,5

y = 0

14. Which one of the following is TRUE about foreign key field for a given table? a) it is a field that uniquely identifies the record in the table b) the values for the foreign key field can have similar values in different record c) the values for the foreign key field cannot have duplicate values in different record d) none of the above


jawaban:

c) the values for the foreign key field cannot have duplicate values in different record


15. Please help The equation of a curve is y=x^3+3x^2-9x+k, where k is a constant. i) Find the coordinates of the stationary points on the curve and their natures. ii) Find the values of k for which the curve has a stationary point on the x-axis. iii) Find the equation of the tangent to the curve at the point where the curve intersects the y-axis. iii) Find the set of values for x for which y=x^3+3x^2-9x+k is increasing function.


[tex]EQ\rightarrow\ y=x^3+3x^2-9x+k\\\\i.\\Stationary\ points:\\\ f(x)=x^3+3x^2-9x+k\\f'(x)=3x^2+6x-9\\f'(x)=0=3x^2+6x-9\\0=(3x-3)(x+3)\\x_1=1\\x_2=-3\\\\Nature:\\f'(x)=3x^2+6x-9\\f''(x)=6x+6\\for\ x=1\rightarrow\ f''(x)=12(positive)\\for\ x=-3\rightarrow\ f''(x)=-12(negative)\\hence\ x_2\ is\ the\ maximum\ point\ and\ x_1\ the\ minimum[/tex]

[tex]ii.\\subsititute\ x_1\ and\ x_2\ to\ f(x)\\x_1\rightarrow (1)^3+3(1)^2-9(1)+k=0\\k_{x_1}=5\\x_2\rightarrow (-3)^3+3(-3)^2-9(-3)+k=0\\k_{x_2}=-27[/tex]

[tex]iii.\\intersects \rightarrow\ x=0\\y=(0)^3+3(0)^2-9(0)+k\\y=k\\y=\ 5/-27\\f'(x)=3x^2+6x-9\\3(0)^2+6(0)-9\\hence\ m_{curve}=-9\\\\for\ k=5\\\rightarrow y-5=-9(x-0)\\\rightarrow y=-9x+5\\\\for\ k=-27\\\rightarrow y+27=-9(x-0)\\\rightarrow y=-9x-27[/tex]

[tex]iv.\\because\ x_2\ is\ the\ maximum\ point,\\the\ function\ will\ incerase\ up\ to\ that\ point.\\\\because\ x_1\ is\ the\ minimum\ point,\\the\ function\ will\ decrease\ up\ to\ that\ point.\\\\Hence,\ the\ set\ values\ for\ x\ which\ f(x)\ is\ incerasing\ are:\\(-\infty,-3)\ and\ (1,\infty)[/tex]

hope these helps :)


16. Diagram 2 shows the graph of the quadratic function f(x)= a(x+1)² +8+2k where a and k are constants.a) State, (i) the range of values of a, (ii) the equation of the axis of symmetry of the curve. (b) Find the value of k. ​


Jawab:

Penjelasan dengan langkah-langkah:

[tex]f(x) = a(x+1)^2+8+2k[/tex]

[tex]f'(x) = 0 = 2a(x+1) \to a = 0\cup x = -1 \to x = -1, a\neq 0\\f(-1) = 12 = a(0)^2+8+2k\to k = 2\\f(x) = a(x+1)^2+12[/tex]

a)

[tex]f''(x) \equiv 2a > 0\to \boxed{\boxed{a > 0}}[/tex]

b)

[tex]f(x) = a(x+1)^2+12 = a(x-(-1))^2+12\to \boxed{\boxed{x_p = -1}}[/tex]

c)

[tex]f'(x) = 0 = 2a(x+1) \to a = 0\cup x = -1 \to x = -1, a\neq 0\\f(-1) = 12 = a(0)^2+8+2k\to \boxed{\boxed{k = 2}}[/tex]


17. given f(x)= [tex] 2^{x} [/tex] find the values of


[tex]\text{Bagian A} \\ f(x)~=~2^x \\ f(4x+3)~=~2^{4x+3} \\ f(2x-1)=2^{2x-1} \\ f(6x-3)~=~2^{6x-3} \\ \text{Maka~:} \\ \\ \displaystyle \frac{f(4x+3)~\bullet f(2x-1)}{f(6x-3)}~~=~~\frac{2^{4x+3} \bullet 2^{2x-1} }{2^{6x-3}}~~=~~2^{(4x+3)+(2x-1)-(6x-3)} \\ \\ \frac{f(4x+3)~\bullet f(2x-1)}{f(6x-3)}~~=~~2^{5}~=~32[/tex]


[tex]\text{Bagian B} \\ f(2x+1)~=~2^{2x+1} \\ f(x-3)~=~2^{x-3} \\ f(3x+5)~=~2^{3x+5} \\ \\ \displaystyle \frac{f(2x+1)~\bullet~f(x-3)}{f(3x+5)}~~=~~\frac{2^{2x+1}~\bullet~2^{x-3}}{2^{3x+5}}~=~2^{(2x+1)+(x-3)-(3x+5)} \\ \\ \\ \frac{f(2x+1)~\bullet f(x-3)}{f(3x+5)}~~~=~~2^{-7}~=~\frac{1}{2^7}~=~\frac{1}{128}[/tex]

18. 4) Which of the following represents all the possible values of x that satisfy the equation below? X X x − 3 2x 2 *​


Nilai x memenuhi persamaan yaitu x = 0 atau x = 4. Soal ini berkaitan dengan materi mencari nilai x dari suatu persamaan.

Penjelasan dengan langkah-langkah

Diketahui :

Koreksi soal, mungkin maksud Anda persamaan x/(x-3) = 2x/2

Ditanyakan :

Solusi dari permasalahan tersebut

Jawab :

Langkah 1

x / (x - 3) = 2x / 2

Jika dipindah ruas akan menjadi :

x . 2  = 2x . (x – 3)

Selanjutnya kita lakukan operasi

  2x  = [tex]2x^{2}[/tex] – 6x

    0  = [tex]2x^{2}[/tex] – 8x

     0 = 2x (x – 4)

 x = 0 atau x = 4

Jadi, x yang memenuhi adalah x = 0 atau x = 4

Pelajari Lebih Lanjut

Materi tentang mencari nilai x dari suatu persamaan brainly.co.id/tugas/26215307

#BelajarBersamaBrainly #SPJ1


19. Find the values of p


f(x) = -x² + 14x + p²
a = -1
b = 14
c = p²

y max = 74
(b² - 4ac)/(-4a) = 74
[14² - 4 . (-1) . p²]/[-4 . (-1)] = 74
(196 + 4p²)/4 = 74
196 + 4p² = 74 . 4
196 + 4p² = 296
4p² = 296 - 196
4p² = 100
p² = 100 : 4
p = ±√25
p = ±5

20. What is the function / formula for finding the sum of all values from the above data? (From Google Spreadsheet)


Jawaban:

untuk Nilai

Penjelasan:

Maaf banget kalau salah yaa


Video Terkait Topik Diatas


Thanks for reading & sharing Serambi Pengetahuan

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