1) Find the area of this shape below!
1. 1) Find the area of this shape below!
Jawaban:
182
Penjelasan dengan langkah-langkah:
15x7= 105
5x11= 55
1/2 x 11 x 4 = 22
105 + 55 + 22 = 182
2. a. find the perimeter of the shapeb. find the area of the shape
Jawaban:
the working and the answer are shown in the pic.
happy learning
#first
3. find the area of this shape
Diketahui:
Tinggi segitiga =6 cm
Jari-jari lingkaran 4 cm
Ditanya:
Luas bangun
Dijawab:
Luas segitiga= 1/2 * alas * tinggi
Luas segitiga= 1/2 * 8 * 6
Luas segitiga= 24
nb: alas segitiga didapat dari jari-jari lingkaran x 2
Luas lingkaran= 3.14 * 4 * 4
Luas lingkaran= 3.14 * 16
Luas lingkaran= 50.24
karena hanya setengah lingkaran maka 50.24 : 2 = 25.12
Jadi luas gabungan dari segitiga dengan setengah lingkaran adalah 24 + 25.15 = 49.12 atau 49.1 (A)
4. Find the area and perimeter of the shape! Diameter = 21 cm. Tolong yaa
Jawaban:
A = 346,5 cm²
P = 66 cm
Penjelasan dengan langkah-langkah:
Area
[tex]A = \pi \times {r}^{2} \\ A = \frac{1}{4} \times \pi \times {d}^{2} \\ A = \frac{1}{4} \times \frac{22}{7} \times 21 \times 21 \\ A = 346.5 \: {cm}^{2} [/tex]
Perimeter
[tex]P = 2 \times \pi \times r \\ P = \pi \times d \\ P = \frac{22}{7} \times 21 \\ P = 66 \: {cm}[/tex]
5. The volume of a box in the shape of a cubeis 2197 cm3. Find the area of one side of the box.
Jawab:
169 cm²
Penjelasan dengan langkah-langkah:
We know that the Volume of a box is 2197 cm^3
then, we need to find its length.
To find it, we need to cubic root the Volume.
Thus, we get
∛2197 = 13 cm.
In order to find one side area, we need to use square formula
Area = Length²
Area = (13 cm)²
Area = 169 cm²
Perhaps this will help you :)
6. What is the area of the right triangle shown below
ANSWER:
60.
Penjelasanya :
(theorema phytagoras) a=[tex]\sqrt{b^{2} -c^{2} }[/tex]
a= 17[tex]\sqrt{17^{2}-8^{2} } = \sqrt{289-64}[/tex]
a=[tex]\sqrt{225} =[/tex]15
(the area of the right triangle) :
1/2 x a x h
1/2 x 8 x 15
= 60
ur welcome:)
7. Find the area of the compound shapes below!
Jawaban:
2.520
Penjelasan dengan langkah-langkah:
9×8×7×5=2.520
semoga bermanfaat
8. What is the area of the triangle shown below
a = 5
b = 5
c = 8
Keliling
= a + b + c
= 5 + 5 + 8
= 18
s = 1/2 x keliling
s = 1/2 x 18
s = 9
Luas
= √(s(s - a)(s - b)(s - c))
= √(9(9 - 5)(9 - 5)(9 - 8))
= √(9 x 4 x 4 x 1)
= √144
= 12 satuan luas
9. 2. Find the area of the shape!10 cm6 cm8 cm
Jawaban:
may I know what shape is it?
10. Find the perimeter of the square below. Area= 64 cm
Jawaban:
32 cm
Penjelasan dengan langkah-langkah:
Luas= s²
64 cm²= s²
(8 cm)²= s²
s= 8 cm
K= 4 × s
K= 4 × 8 cm
K= 32 cm
11. a tailor cut out a small rectangle from a big rectangular piece of cloth. The remaining cloth as shown below has an area of 22m². (a) Find the area of the original piece of cloth.(b) find the breadth of the original piece of cloth.
Jawaban:
A TAILOR CUT OUT A SMALLER RECTANGLE FROM A BIG RECTANGULAR PIECE OF CLOTH. THE REMAINING CLOTH AS SHOWN BELOW HAS AN AREA OF 22M²
Jawab:
(a.) Area of the original piece = 30 m²
(b.) Breadth of the original piece = 5 m
Penjelasan dengan langkah-langkah:
Given that the area (colored dark) A₁ = 22 m²
Length of the original piece (L) = 6 m
length of the cut out piece (l) = 4 m
breadth of the cut out piece (b) = 2 m
(a.) Find the area before the cloth was cut
Let the used cloth be 'x'
x = l(b)
x = 4(2)
x = 8 m²
Therefore the area before the cloth was cut =
A₁ + x =
22 + 8
= 30 m²
Area of the original piece = 30 m²
(b.) Find the breadth of the original piece (B)
L(B) = 30
6B = 30
B = 30/6
B = 5 m
Breadth of the original piece = 5 m
( x c v i )
12. in the figure below BD=DE find the area of the shaded part
AREA
═══════════════════════════
Solutions that match the question!
Solution :The area of the large triangle minus the area of the small triangle.
BD = DE = 1/2 BE = 1/2 96 = 48 cm
Area 1
= 1/2 × 72 × 96
= 72 × 48
= 3.456 cm²
Area 2
= 1/2 × 72 × 48
= 72 × 24
= 1.728 cm²
[tex]\\[/tex]
Area of the shaded part :
= Area 1 - Area 2
= 3.456 - 1.728
= 1.728 cm²[tex]{ \green{ \boxed{ \boxed{ \sf{ {Answer \: by : AdhidMagelang}}}}}}[/tex]
13. in the figure below BD=DE find the area of the shaded part
Answer:
1,728 cm²
Explanation with steps:
BD = DE = 1/2 x 96 cm = 48 cm
area of the shaded part = area of ABC - area of ADC
area of ABC
= 0.5 x AC x BE
= 0.5 x 72 cm x 96 cm
= 3,456 cm²
area of ADC
= 0.5 x AC x DE
= 0.5 x 72 cm x 48 cm
= 1,728 cm²
so the area of the shaded part is
= 3,456 cm² - 1,728 cm²
= 1,728 cm²
14. what is the area of the rectangle shown below?
Jawab:
Penjelasan dengan langkah-langkah:
The area= luas yaa
okee berarti sangat gampang kpk!
Luas persegi panjang= lebar x panjang
maka panjang= 5 3/4 =23/4 cm dan lebar=3 cm
L= pxl
= 23/4 x 3
=69/4
=17 1/4 cm atau 17,25 cm
15. 16. the area of the shape is
Jawaban:
½ x (23+17) x 16
½ x 40 x 16
320 cm²
16. Find the area of the shaded part in the figure below
4. Area = 49.2075 m²
5. Area = 63.25 m²
Penjelasan/Explanation
Number 4
The area of that figure equals to the area of the square minus the area of the semicircle.
The length of each side: s = 9 mRadius of semicircle: r = ½sA = s² – ½πr²
⇔ A = s² – ½π(½s)²
⇔ A = s² – ½(¼πs²)
⇔ A = s² – (1/8)πs²
⇔ A = s²[1 – (1/8)π]
⇔ A = 9²[1 – (1/8)×3.14]
⇔ A = 81(1 – 0.3925)
⇔ A = 81(0.6075)
⇔ A = 49.2075 m²
Number 5
The area of that figure equals to the sum of the area of the right-angled triangle and the area of the semicircle.
Base of triangle: b = 8 mHeight of triangle: h = 6 mRadius of semicircle: r = (½×10) m = 5 mA = ½bh + ½πr²
⇔ A = ½(bh + πr²)
⇔ A = ½(8×6 + 3.14×5²)
⇔ A = ½(48 + 3.14×25)
⇔ A = ½(48 + 78.5)
⇔ A = ½(126.5)
⇔ A = 63.25 m²
KESIMPULAN/CONLUSION4. Area = 49.2075 m²
5. Area = 63.25 m²
17. Find the perimeter and area of the composite figure below. BANTU PLISSS
perimeter = π x d + 12 + 12
perimeter = 3,14 x 12 + 12 + 12
perimeter = 37,68 + 24
perimeter = 61,68
Area = 12 x 12 - π x r x r
Area = 144 - 3,14 x 6 x 6
Area = 144 - 113,04
Area = 30,96
18. A square is divided into 3 parts A, B and C as shown below. The ratio of the area of A to the area of B to the area of C is 5:3:7. Given that the area of A is 75 cm2, find the length of one side of the square.
Penjelasan dengan langkah-langkah:
A : B : C
5 : 3 : 7
Actual A = 75 cm²
75 : 5 = 15
B = 3 x 15 = 45 cm²
C = 7 x 15 = 105 cm²
19. Rectangle A overlaps Square B as shown. The ratio of the area of Rectangle A to the shaded area to the area of Square B is 6:1:4 The area of Rectangle A is 36 cm2. Find the area of the whole figure.
Ratio of the area of Rectangle A =
6 units
6 units = 36 cm2
1 unit = 36 ÷ 6 = 6 cm2
Ratio of total area = 6 + 1 + 4 = 11 units
11 units = 11 x 6 = 66 cm2
The area of the whole figure is 66 cm2.
20. calculate the area of the shaded part of the shape
Jawab:
5,375 [tex]cm^2[/tex]
Penjelasan dengan langkah-langkah:
The area of square is
5×5 = 25
The area of circle is
[tex]\pi[/tex]x2,5x2,5
3,14x2,5x2,5
19,625
The area of shaded part is 25-19,625 = 5,375 [tex]cm^2[/tex]
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