kak..pliss jawab dong...important!plisss find the trigonometric function of the graph. jawab yaa :
1. kak..pliss jawab dong...important!plisss find the trigonometric function of the graph. jawab yaa :
Jawab:
4 tan x°
Penjelasan dengan langkah-langkah:
perhatikan bahwa di kuadran I (sudut 0° sampai 90°) nilai sudutnya positif, maka fungsi trigonometri yang digunakan adalah sinus atau tangen
lalu pada sudut 90° sampai 180° (kuadran II) nilai nya negatif, maka fungsi trigonometri diatas cosinus atau tangen
dari kedua kesimpulan diatas, maka jelas fungsi yang dipakai adalah tangen. perhatikan bahwa
tan 45° = 1
maka
4 tan 45° = 4
maka kemugkinan fungsi diatas berbentuk
4 tan x°
cek
4 tan 135° = 4 tan (180° - 45°) = 4 (-tan 45°) = 4.(-1) = 4×(-1) = -4 (sesuai)
4 tan 225° = 4 tan (180 + 45°) = 4 tan 45° = 4×1 = 4 (sesuai)
Jadi fungsi trigonometri yang dipakai adalah 4 tan x°
2. Evaluate Limit Involving Trigonometric Function
Jawaban:
0
Penjelasan dengan langkah-langkah:
[tex]lim_{x \to0} \frac{secx - 1}{x} \\ = lim_{x \to0} \frac{ \frac{1}{cosx} - 1}{x} \\ = lim_{x \to0} \frac{ \frac{1 - cosx}{cosx} }{x} \\ = lim_{x \to0} \frac{1 - cosx}{xcosx}. \frac{1 + cosx}{1 + cosx} \\ = lim_{x \to0} \frac{1 - {cos}^{2} x}{xcosx(1 + cosx)} \\ = lim_{x \to0} \frac{{sin}^{2} x}{xcosx(1 + cosx)} \\ = lim_{x \to0} \frac{sinx}{x}. \frac{sinx}{cosx} . \frac{1}{1 + cosx} \\ = 1. \frac{sin0}{cos0} . \frac{1}{1 + cos0} \\ = 1.0. \frac{1}{2} \\ = 0[/tex]
Jawab:
[tex]\displaystyle \lim_{x\to0}\frac{\sec x-1}{x}=0[/tex]
Penjelasan dengan langkah-langkah:
[tex]\displaystyle \lim_{x\to0}\frac{\sec x-1}{x}=\lim_{x\to0}\frac{\frac1{\cos x}-1}{x}\\\lim_{x\to0}\frac{\sec x-1}{x}=\lim_{x\to0}\frac{1-\cos x}{x\cos x}\\\lim_{x\to0}\frac{\sec x-1}{x}=\lim_{x\to0}\frac{1-\cos x}{x}\cdot\lim_{x\to0}\frac1{\cos x}\\\lim_{x\to0}\frac{\sec x-1}{x}=\lim_{x\to0}\frac{2(1-\cos x)}{2x}\cdot\lim_{x\to0}\frac1{\cos x}\\\lim_{x\to0}\frac{\sec x-1}{x}=\lim_{x\to0}\frac{2\sin^2\frac12x}{x}\cdot\lim_{x\to0}\frac1{\cos x}\\\lim_{x\to0}\frac{\sec x-1}{x}=\lim_{x\to0}\sin\frac12x\cdot\lim_{x\to0}\frac{2\sin\frac12x}{x}\cdot\lim_{x\to0}\frac1{\cos x}\\\lim_{x\to0}\frac{\sec x-1}{x}=\sin\frac12(0)\cdot2\cdot\frac12\cdot\frac1{\cos 0}\\\lim_{x\to0}\frac{\sec x-1}{x}=0\cdot1\cdot1\\\boxed{\boxed{\lim_{x\to0}\frac{\sec x-1}{x}=0}}[/tex]
3. The posting key has controlling function for the following purpose, which is.....
Jawaban:
The posting key has controlling function for the following purpose, which is.....
1. Transfer of information from financial accounting to management accounting
2. Post document items as debit or credit
3. Type of account to post document items
4. Additional state additional data field
4. Which of the following statements correctly describes the motion of the car shown by the velocity time graph
Mana dari pernyataan-pernyataan berikut benar menjelaskan gerakan mobil yang ditunjukkan oleh kecepatan waktu grafik.
5. Diagram 5 shows the graph of a quadratic function y = f(x)
a. y = 21+4x-x²
0 = 21+4x-x²
0 = (7-x)(3+x)
x = 7 atau x = -3
b. mencari sumbu simetri di turunan pertama:
y = 21+4x-x²
y' = 4 - 2x ; subtitusi y' = 0 (karena pada titik puncak, m=0)
0 = 4 - 2x
2x = 4
x = 2 ← sumbu simetri
6. The status depicts a woman escaping the chains of tyranny which lie at her feet . What is the synonym of depicts?
Jawaban:
synonym of depicts is Represent
7. inverse function of h(x)=2x-9
Rumus:
h'(x) = x - b / a
Jika h(x) = 2x - 9
a = 2
b = -9 => -b = 9
h'(x) = x + 9 / 2
Maaf jika salah
Semoga membantu ^_^
8. The first derivative of the trigonometric function f(x) = tan x - 5 sinx is...~thank you for answering~ :):
Answer:
f'(X) = sec^x - 5 cosx
sedang tidak mood kakak??
9. inverse function of f(x) = 2x + 5
Penjelasan dengan langkah-langkah:
inii cobaaa aku bantu, maaf klo ssalah
10. which graph represents the solution of the inequality -12x > 36
Jawaban:
the working and the answer are shown in the pic.
semangat belajar;))
11. 1.11. Stating the social function of the following expressions!
Jawaban:
Konsep : Menyederhanakan bentuk akar Ingat kembali! √((a+b) + 2√(a.b)) = √a + √b √(x^2) = x Pembahasan : √(8+4√3) = √(8+√(3.16) ) = √(8 + √(3 . 4^2)) = √(8 + √(3.4.4)) = √(8 + 2√12) = √((6+2) + 2√(6.2)) = √6 + √2
12. Which the following function is always positive for all values of x?
bagaimana mengikuti selalu positif dengan semua
13. State the following trigonometric equations[tex] \cos(x + 35 ) = 0.5[/tex]35 itu degree ya.35 darjah
Jawab:
25⁰, 265⁰
Penjelasan dengan langkah-langkah:
14. which graph represents the solution of the inequality -12x > 36
Jawaban:
the working and the answer are shown in the pic.
semangat belajar;))
15. i) the inverse of a function can exists if, and only if, the function f (x) is a one-one mappingii) the domain of f (x) is the domain if f^-1(x)iii) the graph f (x) & f^-1(x) are reflections of each other in the line y=xwhich statement is true?
Subject Function
Statement (i) is wrong. The correct one is that the inverse of the function exists if and only if the function mentioned is bijective function (one-to-one correspondence)
Statement (ii) is wrong. The domain of f(x) is the codomain of [tex] f^{-1}(x) [/tex]
Statement (iii) is wrong.
[tex] f(x) = x \Rightarrow f^{-1}(x)= x [/tex], while y = x and x = y is the same precise equation. The lines are conjoined and hence don't imply what the reflection means.
16. Which of the following modals do has function as necessity/obligation?A.need to B .will C. must D. can
Answer:
C. must
(necessity/obligation = harus/wajib dilakukan)
Maaf jika ada yang salah
17. Find the inverse of each function... 1. F(x)= 1-2x...
Penjelasan dengan langkah-langkah:
Misalkan y = 1 - 2x
[tex]y = 1 - 2x \\ 2x = 1 - y \\ x = \frac{1 - y}{2} \\ {f}^{ - 1} (x) = \frac{1 - x}{2} [/tex]
-DS-
18. What is the social function of the following text? *
Jawaban:
apa fungsi sosial dari teks berikut?
19. Name the following tools.then, match the description (function) terjemahan
Jawaban:
Gambarnya mana mbok...
20. mohon bantuannya The picture is a graph of quadratic function......
Persamaan umum fungsi kuadrat :
f(x) = Ax² + Bx + C
Diketahui grafik fungsi f(x) melewati titik :
» (3 , 0)
=> f(3) = 0
=> A.(3)² + B.(3) + C = 0
=> 9A + 3B + C = 0 ( i )
» (–1 , 0)
=> f(–1) = 0
=> A.(–1)² + B.(–1) + C = 0
=> A - B + C = 0 ( ii )
» (0 , 3)
=> f(0) = 3
=> A.(0)² + B.(0) + C = 3
=> C = 3
Subtitusikan nilai C ke ( i ) :
9A + 3B + C = 0
9A + 3B + 3 = 0
9A + 3B = –3 ( iii )
Subtitusikan nilai C ke ( ii ) :
A - B + C = 0
A - B + 3 = 0
A - B = –3 ( iv )
Eliminasi ( iii ) dan ( iv ) :
( iii ) : 9A + 3B = –3
(iv) × 3 : 3A - 3B = –9
________________ +
12A = –12 => A = –1
Subtitusikan nilai A ke ( iv ) :
A - B = –3
–1 - B = –3 => B = 2
Substitusikan nilai A, B, dan C ke persamaan fungsi kuadrat :
f(x) = Ax² + Bx + C
f(x) = (–1)x² + (2)x + (3)
Jadi, persamaan fungsi kuadrat grafik tersebut adalah : f(x)=–x²+2x+3
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