Determine the angle θ in the right triangle shown.
1. Determine the angle θ in the right triangle shown.
Jawaban:
35,54 derajat
Penjelasan:
ada di dalam gambar
2. What is the area of the right triangle shown below
ANSWER:
60.
Penjelasanya :
(theorema phytagoras) a=[tex]\sqrt{b^{2} -c^{2} }[/tex]
a= 17[tex]\sqrt{17^{2}-8^{2} } = \sqrt{289-64}[/tex]
a=[tex]\sqrt{225} =[/tex]15
(the area of the right triangle) :
1/2 x a x h
1/2 x 8 x 15
= 60
ur welcome:)
3. Name the height of the triangle in the figure below.
Yg loe maksut artiny?
Sebutkan/namakan tinggi dr segitiga digambar berikut.
---------------
askmeenglish (tanya gue Inggris!)
4. In this figure, the right angled triangles ABC and DEF overlap partially. In triangle ABC, AB = 8 cm and BC = 10 cm. In triangle DEF, DE = 12 cm and DF = 9 cm. Find the difference in the areas of the shaded parts! Tolong beserta caranyaa yaa
Area ∆ABC
A1 = ½ • AB • BC
A1 = ½ • 8 • 10
A1 = 40 cm²
Area ∆DEF
A2 = ½ • DE • DF
A2 = ½ • 12 • 9
A2 = 54 cm²
red area = x
purple area = 40 - x
blue area = 54 - x
the difference blue area and purple area
∆A = (54 - x) - (40 - x)
∆A = 14 cm² ← jwb
5. Use the component method to add the vectors a and b shown in figure p3.15.express the resultant a+b in unit-vector natation
ini soal tentang voktor lah
6. In the figure, ABCDE is made up of triangle ABE and square BCDE. AE = ED = 8 cm. Find the area of the figure.
Jawab:
The area of the figure is [tex]{\bf96\:cm^2}[/tex]
Penjelasan dengan langkah-langkah:
The area of figure ABCDE:
A = the area of triangle ABE + the area of square BCDE
= area 1 + area 2
= A₁ + A₂
AE = ED = 8 cm
BE = CD = 8 cm
1st solutionA₁ = the area of triangle ABE
A₁ = [tex]\frac{1}{2} \times AE \times BE[/tex]
A₁ = [tex]\frac{1}{2} \times 8 \times 8[/tex]
A₁ = 4 × 8 = 32 cm²
A₂ = the area of square BCDE
A₂ = ED × CD
A₂ = 8 × 8 = 64 cm²
So, A = area 1 + area 2 = A₁ + A₂ = 32 cm² + 64 cm² = 96 cm²
2nd solutionThe area of triangle ABE = 1/2 × the area of square BCDE, because AE = ED, and it's obvious that BE = CD.
So, the area of figure ABCDE = (1/2 + 1) × the area of square BCDE
[tex]Area_{ABCDE} = (1 + \frac{1}{2} ) \times Area_{BCDE}\\= \frac{3}{2} \times Area_{BCDE}\\= \frac{3}{2} \times (8 \times 8)\\= \frac{3}{2} \times 64\\= 3 \times 32\\= {\bf 96\:cm^2}[/tex]
7. The figure is not drawn to scale. Find the area of the shaded triangle.
Jawaban:
484
Penjelasan dengan langkah-langkah:
Area of triangle = Base x Height
= 22 x 22
= 484
So, the area of the shaded triangle is 484
8. What is the area of the triangle shown below
a = 5
b = 5
c = 8
Keliling
= a + b + c
= 5 + 5 + 8
= 18
s = 1/2 x keliling
s = 1/2 x 18
s = 9
Luas
= √(s(s - a)(s - b)(s - c))
= √(9(9 - 5)(9 - 5)(9 - 8))
= √(9 x 4 x 4 x 1)
= √144
= 12 satuan luas
9. in the figure ABCDE is made up of triangle ABE and square BCDE. AE=ED=8cm. find the area of the figure
Jawaban:
From the questions we know that BCDE is a square and ED = 8cm,
which means BC=CD=ED=EB= 8cm
That means the area for BCDE is side x side or 8 x 8 = 64cm²
since AE = ED and we know that triangle is half of a square
that means the area for ABE = 1/2 x 64= 32cm²
ABCDE = BCDE + ABE
= 64cm² + 32cm²
=96cm²
10. Find the corresponding height for base AB of triangle ABC in the figure below.
Jawaban:
(1) and (3)
Penjelasan dengan langkah-langkah:
Corresponding height = garis tegak lurus
jadi, garis tegak lurus garis AB = (1) dan (3)
11. 2. The figure shows a semicircle and an equilateral triangle. Find the perimeter of the figure. (Take it 3.14) att
Jawaban:
semoga bermanfaaat...........................
12. (1)Maing Unknown AnglesIn the following figure, triangle LMO is an equilateral triangle andtriangle MNO is an isosceles triangle. Find ZMNOLM MN12]In the following figure, triangle PQT is an equilateral triangleTriangle PRS is an isosceles triangle. ZQPR = RPS = SPT. Find ZPRSTRS
Jawaban:
120⁰80⁰detail cara dan jawabannya seperti di foto ya.
semangat belajar....
#bintang5dan<3yaaa;))
13. In the figure, ABCG and DEFG are squares and BFG is a triangle. AG = 27 cm and GF = 18 cm. Find the area of triangle BFG.
Jawab:
Pertama, kita akan menghitung luas segitiga di gambar pertama, lalu kita akan mengurangi luas segitiga tersebut dengan luas segitiga di gambar kedua.
Penjelasan dengan langkah-langkah:
Untuk menghitung segitiga pertama, kita bisa menggunakan rumus persegi panjang. Kita tahu lebar dari AG adalah 27cm, dan lebar GF adalah 18cm. Sedangkan tingginya adalah tinggi dari persegi ABCG, yaitu 27cm. Setelah mendapat luas persegi panjang, kita bisa mendapatkan segitiga dengan membagi luas dengan 2.
((27 + 18) × 27) ÷ 2
(45 × 27) ÷ 2
1215 ÷ 2
607,5.
Setelah mendapat segitiga A, kita dapat memotong luasnya dengan luas segitiga B.
607,5 - ((27 × 27) ÷ 2)
607,5 - (729 ÷ 2)
607,5 - 364,5
243 (Jangan lupa satuannya ya)
Jadi, luas segitiga BFG adalah 243cm.
14. In the figure, ABCD is a parallelogram and AED is a right-angled triangle. If the area of AAED is 25 cm², and the lengths of AE and EB are in the ratio 1 : find the area of the trapezium BCDE.
Penjelasan dengan langkah-langkah:
apakah ada gambarnya soalnya kalau tidak ada gambar nya saya tidak bisa Jawab
15. PQR is a triangle with area 6 cm² as shown in the diagram above.Calculate
Point (a)
Reflex angle is an angle between 180 to 360 degrees.
You can calculate QPR acute (0 < x < 90) angle first by cosine.
cos x = 4/5
x = 37
This is a default-memorizable angle which is often used in Mathematics and Physics.
Reflex angle = 360 - acute angle
= 360 - 37 = 323 degrees
Point (b)
Area of triangle is:
A = 1/2 × base × height
6 = 1/2 × base × 4
12 = 4 base
base = 3 cm
16. A glass house is in the shape as shown in the figure . calculate total area of glass needed and calculate the volume of the glass house
Jawab:
Total Luas seluruh bangunan = L prisma segitiga + L balok
= 248 m² + 292 m² = 540 m²
Total Volume seluruh bangunan = V prisma segitiga + V balok
= 60 m³ + 336 m³ = 396 m³
Penjelasan dengan langkah-langkah:
Bangunan ini adalah gabungan dari prisma segitiga dan balok.
Diketahui :
Prisma segitiga : alas = 5 m
tinggi alas = 6 m
tinggi prisma = 11 m - 7 m = 4 m
Ditanya : L = ?
V = ?
L = 2 X Luas alas + Keliling alas + tinggi
= 2 X (1/2 X 5X6) + (5+5+6) x 4
= 2 x (15 + 16 x 4)
= 2 x 124 = 248 m²
Volume = Luas alas X tinggi
= (1/2 X 5X6) X 4
= 60 m³
Sekarang kita hitung balok.
Diketahui : p = 8 m
l = 6 m
t = 7 m
Ditanya : L = ?
V = ?
L balok = 2 (pl + pt + lt)
= 2 (8X6 + 8X7 + 6X7)
= 2 (48+56+42)
= 2 x 146 = 292 m²
Volume balok = pxlxt
= 8 X 6 X 7
= 336 m³
Total Luas seluruh bangunan = L prisma segitiga + L balok
= 248 m² + 292 m² = 540 m²
Total Volume seluruh bangunan = V prisma segitiga + V balok
= 60 m³ + 336 m³ = 396 m³
17. A square of side 2 cm is cut from a triangle as shown. Find the area and perimeter of the figure.
Jawab:
24
Penjelasan dengan langkah-langkah:
4+2+6+2+6+10
Jawaban:
Areanya 20cm
perimeternya 24 cm
Penjelasan dengan langkah-langkah:
penjelasan ada di foto sori klo salah
18. figure B is made up of four identical right angled triangles as shown in figure A. Four times the perimeter of figure A is 96cm. The perimeter of Figure B is 48cm. What is the lenght of XY?tolong dibantu sesegera mungkin ya.. thanks. #math#matematika#triangle#perimeter
Jawaban:
6 cm
Penjelasan dengan langkah-langkah:
4(Keliling gambar A) = 96 cm
Keliling gambar A = 24 cm
Gunakan tripel Pythagoras
Segitiga 3-4-5 adalah segitiga siku-siku dan kelilingnya adalah (3+4+5) cm = 12 cm
Kalau mau dapatkan segitiga siku-siku dengan kelilingnya adalah 24 cm, maka tripel Pythagorasnya adalah 6-8-10 (Cuma dikali 2). Karena XY(alas segitiga) lebih pendek daripada tinggi segitiga, maka XY = 6 cm
19. A figure is made up of a rectangle and a semicircle as shown in the diagram below. what is the area of the figure?
Jawab:
Area itu bahasa inggris dari Luas, maka
Area of square = S x S
= 7 x 7
= 49 cm²
Radius = Diameter / 2
= 7 / 2
= 3.5 cm
Area of [tex]\frac{1}{2}[/tex] circle = [tex]\frac{1}{2}[/tex] x [tex]\pi[/tex] x r²
= [tex]\frac{1}{2}[/tex] x [tex]\frac{22}{7}[/tex] x 3.5²
= 19.25 cm²
Are of the figure = 49 + 19.25 = 68.25 cm²
Penjelasan:
phi [tex](\pi )[/tex] untuk [tex]\frac{22}{7}[/tex] digunakan apabila jari-jari/radius berkelipatan 7, sedangkan
phi untuk 3.14 digunakan apabila jari-jari/radius tidak berkelipatan 7
20. The figure ABCDE is made up of Triangle CDE and Rectangle ABCE. Find the area of the figure
Jawaban:
[tex]96 {cm}^{2} [/tex]
Penjelasan dengan langkah-langkah:
penjelasan ada difoto
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