what is the function of high- density lipoprotein?Brainly
1. what is the function of high- density lipoprotein?Brainly
Jawaban:
Although high-density lipoproteins (HDL) possess many features that contribute to the association between elevated HDL cholesterol and protection from atherosclerosis, these lipoproteins may be modified in certain individuals and/or circumstances to become proinflammatory. The ability of HDL to inhibit or paradoxically to enhance vascular inflammation, lipid oxidation, plaque growth, and thrombosis reflects changes in specific enzyme and protein components. The anti-inflammatory and proinflammatory functional properties of HDL can now be assessed using cell-based and cell-free assays. Acute or chronic systemic inflammation and the metabolic syndrome appear to render HDL proinflammatory. In contrast, statins and experimental agents such as apolipoprotein A-1 mimetics render HDL more anti-inflammatory. Functional characterization of HDL is a promising method for enhanced assessment of cardiovascular risk and effectiveness of risk reduction.
Kalo G Salah
Maaf Jika Ada Kesalahan
2. What is the use of density in the calculation of percentage by mass?
Penjelasan:
Apa gunanya massa jenis dalam perhitungan persentase massa?
Jawaban:
Density can also be used to determine the mass percent of an unknown concentration.
Penjelasan:
maaf kalau salah, semoga dapat terbantu
3. what is the use of density in the calculation of percentage by mass
Jawaban:
%B = p 10 B / MrPenjelasan:
semoga bermanfaat
4. The density of aluminium is 2.7 kg/m3. If the mass of aluminium is 8.1 grams, what is the volume of the aluminium in m3?
Jawaban:
[tex]\sf\large{V=0,003\ m³}[/tex]
Penjelasan dengan langkah-langkah:
The known things are;
[tex]\sf\large{ρ = 2,7\ kg/m³}[/tex]
[tex]\sf\large{m = 8,1\ g = 0,0081\ kg}[/tex]
The asked of the volume of aluminium
The answer is;
Use the formula;
[tex]\sf\large{ρ} = \LARGE{\frac{m}{V}}[/tex]
[tex]\sf\large{V} = \LARGE{\frac{m}{ρ}}[/tex]
[tex]\sf\large{V} = \LARGE{\frac{0,0081}{2,7}}[/tex]
[tex]\sf\large{V = 0,003\ m³}[/tex]
So, the volume of the aluminium is [tex]\sf\large0,003\ m³[/tex]
5. steel block has mass 40 g it is in the form of a cube each edge of the cube is 3 cm long so what is the density
Jawaban:
1.481g/cm³
Penjelasan:
density = mass/ volume,
volume of cube is s³
mass = 40 g
v = 3.3.3= 27 cm
density = 40/27
= 1.481 g/cm³
6. An alloy is made by combining 900 g of copper with 400 g of iron. If the densityof copper is 9 g/cm and density of iron is 8 g/cm', what is the density of the alloy?(assume that the volume of each metal does not change during mixing.)
ρ(cop) = 9 gr/cm³
ρ(iron) = 8 gr/cm³
ρ = m/Vol
Vol = m/ρ ~ constant!
ρ' = ρ(cop) + ρ(iron)
= 9 + 8
= 17 gr/cm³ ~ 17 × 10³ kg/m³ ✓✓
7. Most substances contract when they freeze so that the density of a substance's solid is______________of its liquid. A. Than the higher density B. Higher than the density C. The density is higher than that D. The higher the density
jawabannya yang B.Higherthanthedensity
8. The density of water is 1.0g/cm3. This is useful as it means we can measure themass of water and easily work out its volume. A. What is the mass of 1cm³ of water? B. What is the mass of 20cm³ of water? C. What is the volume of 10g of water? D. What is the volume of 22.5g of water
Jawaban:
The density of water is 1.0g/cm3. This means 1 g of water mass equals to 1 cm³ of water volume.
a. 1 cm³= 1g
b. 20 cm³= 20g
c. 10 g= 10 cm³
d. 22.5g = 22,5 cm³
semangat belajar
#first
9. A measuring cylinder has a mass of 120 g when empty. When it contains 50 cm3 of a liquid, the total mass of the measuring cylinder and the liquid is 160 g. What is the density of the liquid?
Mass of cylinder (empty) = 120 gram
Mass of cylinder (with liquid) = 160 gram
Volume of liquid = 50 cm³
Density of the liquid (ρ) = ?
Answer:
Find the mass of liquid
With liquid - Empty
= 160 gram - 120 gram
= 40 gram
So, the mass of the liquid is 40 gram
Find the density of the liquid
[tex]\rho=\frac{mass}{Volume} \\\rho=\frac{40\ gr}{50\ cm^3} \\\rho=\frac{40}{50}\ gr/cm^3 \\\rho=\frac{4}{5}\ gr/cm^3 \\\boxed{\rho = 0,8\ gr/cm^3}\\or\\\boxed{\rho = 800\ gr/cm^3}\\[/tex]
Hope it helps :)
10. ARCHIMEDES LAW: Determine the density of the cork if 75% of volume cork is dipping into water and water density 1 gram/cm3!
Fh= w
roair. g . Vbenda yg tercelup = robenda . g. Vbenda
1 . 10. 75%V = robenda. 10. V
1/4V = robenda . V
ro benda = 1/4 = 0,25 gram/cm³
11. An object has a mass of 10 grams and volume of 2mL. What is the density of the object
Jawaban:
ro(density)=m:v
10:2=5
Penjelasan:
12. what is the density of an object which mass is 50g and volume is 20cm3?
semoga membantuuuuuuuuuDensity is Mass/Volume
So 50g/20cm3
The answer is 5/2 or 2 1/2 g/cm3
Sorry for the wrong format.
13. 1. A cube has length of 7 cm a width of 8 cm and a height of 2 cm. What is its volume? 2. The density if aluminum is 2.7 g/ml. If the aluminum has a volume of 20 ml, what is the mass of the aluminum? 3. A marble has a volume of 20 ml. It also has a mass of 10g. Calculate the density of the marble. Tolong sertakan cara mengerjakannya
1. its volume = 7 × 8 × 2
= 112 cm
2.mass = the density × volume
= 2,7 g / ml × 20 ml
= 54 gram
3.the density= mass / volume
= 10 / 20
= 0,5 g / ml
semoga bermanfaat
14. what is the density of diamond that has a mass of 70g and volume of 20cm³
Jawaban:
density = mass/ volume = 70g/20 cm³ = 3,5 g/cm³
15. What is the density of a substance that has a volume of 5,5 cm3 and a mass of 10g?
Jawaban:
1,81 g/cm³
Penjelasan:
Density=Mass/Volume
=10/5,5
=1,81 g/cm³
Density=Massa Jenis
Mass=Massa
Volume=Volume
16. A bar of gold has a mass of 3,8 kg. If the density of gold is 19 g/cm3, what is the volume of the gold?
Penjelasan:
so, the bar of gold has a mass : 3,8 kg ⇒ 3800 g
and the density of gold is : 19 g/cm³
this is the formula : Volume = mass / density
V = 3800 g / 19 g/cm³
V = 200 cm³
the answer is : V = 200 cm³
17. A 100 mm cube of a substance weighs 8 n. what is density and relative density
Jawaban:
800 kg/m³
Penjelasan:
Rumus dari massa jenis adalah:
ρ = m / V
Diket:
Panjang = 100mm = 0,1 m
Volume kubus = r³ = 0.001 m³
berat = 8 newton,
massa = berat/percepatan gravitasi
= 8/10 = 0,8 kg
massa jenis = 0,8 / 0.001
= 800 kg/m³
Jadikan jawaban terbaik yaa.
18. the metal uranium has a density of 19g/cm pangkat 3 ...what is the mass of a block of uranium with a volume of 21,5 cm pangkat 3...
massanya adalah = 21,5 x 19 g = 408,5 gramm=ro×v
=19×21,5
=408,5 g
=0,4085 kg
19. A solution of H2SO4 with a molal concentration of 8.010 m has adensity of 1.354g/mL. What is the molar concentration of thissolution?
Answer with explanation:
You are given a solution of sulphuric acid with a molal concentration of 8.010 m and its density is 1.354 g/mL.
And we also know that the molar mass of sulphuric acid which is 98.079 g/mol.
◈ ◈ ◈
With the known datas, we work out the molar concentration in mol/L.
◈ ◈ ◈
The relation between molarity, molality and density is described within the following equation.
[tex]\frac{1}{m} = \frac{d}{M}-\frac{Mr}{1000}[/tex]
Where,
Density (d) = 1.354 g/mL
Molecular mass of solute (Mr) = 98.079 g/mol
Molality (m) = 8.010 m
Molarity (M) = ... mol/L
◈ ◈ ◈
So then,
[tex]\frac{1}{8.010\ m} = \frac{1.354\ g/mL}{M}-\frac{98.079\ g/mol}{1000}[/tex]
[tex]0.1248\ m = \frac{1.354\ g/mL}{M}-0.098079\ g/mol[/tex]
[tex]\frac{1.354\ g/mL}{M} = 0.098079\ g/mol+ 0.1248\ m[/tex]
[tex]\frac{1.354\ g/mL}{M} = 0.222879\ g/mmol[/tex]
[tex]M = \frac{1.354\ g/mL}{0.222879\ g/mmol}[/tex]
[tex]M = 6.075\ mol/L[/tex]
◈ ◈ ◈
Therefore, the molar concentration of said acid solution is 6.075 mol/L.
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~I hope this helps you~
20. If 5 litres of a liquid has a mass of 850 g what is the density of the liquid in g/cm³
Jawaban:
0,17 g/cm^3
Penjelasan:
mass = 850 g
volume = 5 litres = 5.000 cm^3
density = mass/volume
= 850/5.000
= 0,17 g/cm^3
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