Home » » The Sum Of Sharon s And John s Ages Is 70

The Sum Of Sharon s And John s Ages Is 70

Posted by Serambi Pengetahuan on Minggu, 16 Oktober 2022


The Sum Of Sharon s And John s Ages Is 70

The sum of the ages of John and Julie is 40. Five years ago, John wa twice as old as Julie. How old John when Julie was born?

Daftar Isi

1. The sum of the ages of John and Julie is 40. Five years ago, John wa twice as old as Julie. How old John when Julie was born?


Penjelasan dengan langkah-langkah:

Jo + Ju = 40... (1)

Jo - 5 = (Ju-5) * 2

Jo - 2Ju = -5....(2)

eliminasi (2)-(1)

-3Ju = -45

Ju = 15 tahun

Jo = 40-15 = 25 tahun

Joh when Julie was born

= 25-15=10yrs old

John= A

Julie= B

persamaan pertama

A+B = 40

persamaan kedua

(A-5) = 2*(B-5)

A-5 = 2B - 10

A - 2B = -5

persamaan 1 dan 2

A + B = 40

A - 2B = -5

___________ -

3B = 45

B = 15 thn ---» sekarang

umur A (sekarang)

40-15 = 25 tahun

jika sekarang B berumur 15 thn maka B lahir 15 tahun yang lalu

umur John 15 thn yg lalu yaitu 25 - 15 = 10 tahun

John was 10 years old when Julie was born


2. The ages of three siblings,Leon,Kelley and Jack are in the ratio 3:5:6. The sum of their ages is 42 years.How old is Kelly?


ratio = 3:5:6
Leon = 3
Kelley = 5
Jack = 6

sum ratio = 3+5+6 = 14
sum age = 42

leon = 3/14 x 42 = 9
Kelley = 5/14 x 42 =15
Jack = 6/14 x 42 = 18

so.. kelley age is 15 year

thanks
     











3. Simon is 6 years older than John and Matthew is 3 years younger than John. If the sum of their ages is 66. Form an equation in x and find Simon's age and Matthew's age.


Jawab:

Penjelasan dengan langkah-langkah:

simon = 6 + john

mathew = john -3

john + mathew + simon = 66

subtitute:

john + (john -3) + (6+john) = 66

3john = 63

john = 21

simon = 6 + john = 6+21=27

mathew = john - 3 = 21-3=18

Jawaban:

S = J + 6

M = J - 3

S + M + J = 66

S? M?

S + M + J = 66

(J + 6) + (J - 3) + J = 66

3J = 63

J = 21

S = J + 6

= 21 + 6

= 27

M = J - 3

= 21 - 3

= 18


4. The oak tree is 11 times as old as the garden. The sum of their ages is 108 years. How old is each the garden and tree?


Jawaban:

TG = 9

TOG = 99

Penjelasan dengan langkah-langkah:

TOT = 11 TG

TOT + TG = 108

11TG + TG = 108

12 TG = 108

TG = 108/12

TG = 9

TOT = 11.9

TOT = 99


5. The ages of three sibling, Leon, Kelly and Jack are on the radio 3:5:6. The sum of their age is 42 years. How old is Kelly


Kelly : 5/14×42=15
14 came from 3 + 5 + 6

6. The sum of two numbers is 20 and the sum of their squares is 272. Find the firstnumber​


Jawab:

4 or 16

Penjelasan dengan langkah-langkah:

Let the numbers be x and y

x + y = 20

sum of their squares is 272 so x^2 + y^2 = 272

Find the first number,

We know that x^2 + y^2 = (x + y)^2 - 2xy

so 272 = 20^2 - 2xy

272 = 400 - 2xy

2xy = 128

xy = 64

We know that x + y = 20 and xy = 64, so we can make quadratic equation,

let a1 = x and a2 = y

a^2 - 20a + 64 = 0

(a - 16)(a - 4) = 0

a = 16 or a = 4

So the first number can be 4 or 16

If the first number less than the second, the answer is 4

Semoga terbantu :)

IG: @djie.jemmy

Jawab:

4 or 16

Penjelasan dengan langkah-langkah:

If the first number is [tex]x[/tex] and the second one is [tex]y[/tex],

we can write:

[tex]x + y = 20[/tex]

[tex]x^{2} + y^{2} = 272[/tex]

Then

[tex]x = 20 - y[/tex]

Substitute [tex]x = 20 - y[/tex] to [tex]x^{2} + y^{2} = 272[/tex]

[tex](20 - y)^{2} + y^{2} = 272[/tex]

[tex]400 - 40y + y^{2} + y^{2} = 272[/tex]

[tex]2y^{2} - 20y + 128 = 0[/tex]

Factorize the equation and we get:

[tex](y-16)(y-4) = 0[/tex]

[tex]y = 16[/tex] ∨[tex]y = 4[/tex]

If we substitute [tex]y = 16[/tex] to [tex]x = 20 - y[/tex], we get [tex]x = 4[/tex]

So, we can conclude that both numbers are 4 and 16.


7. if twice the age of son is added to age of father, the sum is 56.but if wice the age of the father is added to the age of son, the sum is 82.fund the ages of father and son.....? tolong di jawab ya​


Jawab:

son age (x) =10

father age (y) = 36

Penjelasan dengan langkah-langkah:

Solve the following system:

y + 2 x = 56

2 y + x = 82

In the first equation, look to solve for y:

y + 2 x = 56

2 y + x = 82

Subtract 2 x from both sides:

y = -2 x + 56

2 y + x = 82

Substitute y = -2 x + 56 into the second equation:

y = -2 x + 56

2 (-2 x + 56) + x = 82

2 (-2 x + 56) + x = x + (-4 x + 112) = -3 x + 112:

y = -2 x + 56

(-3 x + 112) = 82

In the second equation, look to solve for x:

y = -2 x + 56

-3 x + 112 = 82

Subtract 112 from both sides:

y = -2 x + 56

-3 x = -30

Divide both sides by -3:

y = -2 x + 56

x = 10

Substitute x = 10 into the first equation:

y = 36

x = 10


8. Amirah is 4 years older than priya and shirley is 2 years younger than priya. If the sum of their ages is 47, find their respective ages.


Jawaban:

amirah = a

priya = b

shirley = c

a = b + 4

c = b - 2

a + b + c = 47

(b + 4) + b + (b - 2) = 47

3b + 2 = 47

3b = 47 - 2

3b = 45

b = 45/3

b = 15

a = b + 4 = 15 + 4 = 19

c = b - 2 = 15 - 2 = 13

amiras is 19 years old

priya is 15 years old

shirley is 13 years olg


9. Rui Feng is twice as old as Raj and Kahirul is 5 years younger than Raj. If the sum of their ages is 59 years, find their respective ages!


Jawaban:

Rui Feng: 32 th

Raj: 16 th

Kahirul: 11 th

Penjelasan dengan langkah-langkah:

semoga membantu


10. A sum of money is divided among John, Joshua and Raymond in the ratio 3:7:11. IfRaymond has $168 more than John, find the sum of money.​


Jawaban:

$441

Penjelasan dengan langkah-langkah:

John : Joshua : Raymond = 3 : 7 : 11

Raymond has $168 + John.,

Sum of money?

If m = money,

then John : Joshua : Raymond, 3m : 7m : 11m

Raymond = 168 + John

11m = 168 + 3m

8m = 168

m = 21

Sum of money:

= 3m + 7m + 11m

= 3(21) + 7(21) + 11(21)

= 63 + 147 + 231

= $441


11. I. the sum of ages of pamela and randy is 90 years. ii. sally is 10 years younger than randy. the average age of pamela, quentin, randy, and sally is 50 years. how old is randy?


The average age of pamela, quentin, randy, and sally is 50 years. Randy has 20 old years. Because the sum makes the result is 20 old years.

Pembahasan

Dalam mencari umur Randy kita dapat menggunakan cara matematika yaitu dengan cara:

pamela+randy=90sally=randy-10sally=90-pamela-10sally+randy+pamela=10090-pamela-10+randy+pamela=100 Maka dari langkah 5 menghasilkan hasil Randy =20

Aljabar adalah bidang matematika yang mempelajari struktur, hubungan, dan himpunan dengan menggunakan simbol, yang biasanya berupa huruf, sebagai alat penyederhanaan dan untuk membantu menyelesaikan masalah aritmatika. Aljabar pada dasarnya adalah proses dasar dari masalah matematika. Semua masalah matematika dapat diselesaikan dalam aljabar. Contoh aljabar: Penjumlahan, pengurangan, pembagian, dan perkalian variabel.

Pelajari lebih lanjut

Pelajari lebih lanjut materi tentang aljabar: https://brainly.co.id/tugas/984983

#BelajarBersamaBrainly #SPJ1


12. the ages of the three children in the Jones family add up to 14. if their ages are multiplied together, the result is 70. what is the ages of the eldest child? ​


Jawab:

7 years old

Penjelasan dengan langkah-langkah:

Umur Anak pertama = 2

Umur anak kedua = 5

Umur anak ketiga = 7

Caranya di cocokan saja


13. The ages of three siblings, Leon, Kelly and Jack are in the ratio 2 : 3 : 7. The sum of their ages is 72 years. How old is Kelly?


Kelly

3/12 × 72

= 1/4 × 72

= 18 years old

~hope that helps ~


14. the sum of 3 even number is 90 the sum of the biggest and the smallest number is​


Jawaban:

jumlah dari 3 bilangan genap adalah 90 hasil penjumlahan dari bilangan terbesar dan terkecil


15. the sum of 3³ and 9² is


Kelas 6 Matematika
Bab Pangkat Tiga

3³ + 9²
= 27 + 81
= 108
= 4 x 27
= 2² x 3³di artikan jika dijumlahakn 3² dan 9² brp

3³= 27 , 9²= 81
81 ditambah 27 = 108
 c. jawabannya . krn 2² =4 dan 3³ =27 = 4 ×27 =108 . sesuai dengan jumlah soal nya

16. the sum of 461 and 129 is


461+129= 590

moga bantu

17. if the sum of the 2nd and 8th terms is 40 and the sum of the 3rd and 6th terms is 36, what is 5th terms?


Jawaban:

maaf kuarang jelas coba transelete ke indo


18. Ahmad is twice as old as Bobby, John is 7 years younger than Ahmad. If the sum of their ages is 38,how old are the three boys? pakai cara y​


Jawab:

ahmad = 18 y.o.

john = 11 y.o.

bobby = 9 y.o.

Penjelasan dengan langkah-langkah:

Ahmad is 2x old as Bobby

John is 7 years younger than Ahmad

Thus:

a = 2b, j = a - 7, b = a/2,

so:

a/2 + a + a - 7 = 38

5a/2 = 45

5a = 90

a = 90/5 = 18

j = 18 - 7 = 11

b = 18/2 = 9


19. anna is 6 years older than cheryn, and mansion is 8 years older than anna. if the sum of their ages 44, find the respective ages​


Jawab:

Penjelasan dengan langkah-langkah:

anna = x

cheryn = y

mansion = z

x = y + 6 ---> y = x - 6

z = x + 8

x + y + z = 44

x + (x-6) + (x+8 ) = 44

3x + 2 = 44

3x = 44-2

3x = 42

x = 42/3

x = 14  Anna

y = x - 6 = 14 - 6 = 8    cheryn

z = x + 8 = 14 + 8 = 22   mansion

Cheryn = 8 tahun

Anna = 14 tahun

Mansion = 22 tahun


20. The sum of 438 and 241 Is


Jawaban:

438 + 241 = 679

Semoga membantu :)


Video Terkait Topik Diatas


Thanks for reading & sharing Serambi Pengetahuan

Previous
« Prev Post

0 komentar:

Posting Komentar

Cari Blog Ini

Popular Posts

Diberdayakan oleh Blogger.

Follow Us