3 liters of N2 at 0 oC and 10 atm pressure are expanded Isothermally against a constant pressure 2 atm until the pressure of gas is 5 atm. Assuming the gas to be ideal, what are the value of w, AE, AH dan q for the system
1. 3 liters of N2 at 0 oC and 10 atm pressure are expanded Isothermally against a constant pressure 2 atm until the pressure of gas is 5 atm. Assuming the gas to be ideal, what are the value of w, AE, AH dan q for the system
Jawaban:
w = 4.615 litersatm
AE = 0
AH = 4.615 litersatm
q = 9.230 liters*atm
Penjelasan:
The expansion of the gas is isothermal, meaning that the temperature of the gas remains constant during the expansion. This means that the change in internal energy, AE, of the gas is zero.
The work done by the gas, w, is the product of the pressure of the gas and the change in volume of the gas. The initial volume of the gas can be calculated from the ideal gas law:
PV = nRT
where P is the pressure of the gas, V is the volume of the gas, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature of the gas.
Substituting the known values, we get:
(10 atm)(V) = (3 liters)(0.08206 Latm/molK)(273.15 K)
Solving for V, we find that the initial volume of the gas is 0.923 liters.
The final volume of the gas can be calculated in the same way, using the final pressure of 5 atm:
(5 atm)(V) = (3 liters)(0.08206 Latm/molK)(273.15 K)
Solving for V, we find that the final volume of the gas is 1.846 liters.
The work done by the gas is then:
w = (5 atm)(1.846 liters - 0.923 liters) = 4.615 liters*atm
The change in enthalpy, AH, of the gas is equal to the change in internal energy plus the work done by the gas. Since the change in internal energy is zero, the change in enthalpy is also equal to the work done by the gas:
AH = w = 4.615 liters*atm
The heat transfer, q, for the system is the change in enthalpy of the gas plus the work done by the gas:
q = AH + w = 4.615 litersatm + 4.615 litersatm = 9.230 liters*atm
Thus, the values of w, AE, AH, and q for the system are:
w = 4.615 litersatm
AE = 0
AH = 4.615 litersatm
q = 9.230 liters*atm
2. The Vander Wali's equation is given as:(P+a/v^² ) (V-b)=RTwhere P is pressure, V is volume, T is temperatureand R is gas constant What are the units of constant
Jawaban:
R = gas constant
R = 8.314 .......
The unit is J * K^-1 * mol ^-1
3. Eight moles of helium gas with an initial volume of 50 liters and a pressure of 6 atmospheres are isobarically compressed to a final gas temperature of -150 degrees Celsius. Determine the volume of gas and heat that must be eliminated from the system if the Cpm of gas is 22 J/mol.K.
Jawaban:
The heat that must be eliminated from the system is 1521.2 J.
Penjelasan:
To solve this problem, we need to use the ideal gas law, which states that the volume of a gas is directly proportional to its temperature (measured in Kelvins) and inversely proportional to its pressure. The ideal gas law is given by:
PV = nRT
where P is the pressure of the gas, V is its volume, n is the number of moles of the gas, R is the universal gas constant, and T is the temperature of the gas in Kelvins.
In this case, we are given that the pressure of the gas is 6 atmospheres, the number of moles of the gas is 8, and the gas constant is 8.314 J/mol.K. The initial temperature of the gas is not given, but we are told that the gas is being compressed to a final temperature of -150 degrees Celsius. To use the ideal gas law, we need to convert this temperature to Kelvins by adding 273.15 to the temperature in Celsius:
Tfinal (in Kelvins) = -150 + 273.15 = 123.15 K
We can now use the ideal gas law to calculate the final volume of the gas:
Vfinal = (nRT) / P = (8 * 8.314 * 123.15) / 6 = 205.7 liters
To determine the heat that must be eliminated from the system, we can use the equation for isobaric heat capacity, which is given by:
q = Cpm * (Tfinal - Tinitial)
where q is the heat that must be eliminated from the system, Cpm is the heat capacity of the gas at constant pressure, Tfinal is the final temperature of the gas, and Tinitial is the initial temperature of the gas. In this case, we are given that Cpm is 22 J/mol.K. We need to determine the initial temperature of the gas in order to calculate the heat that must be eliminated from the system.
To do this, we can use the ideal gas law to solve for the initial volume of the gas, given that the initial pressure and number of moles of the gas are known:
Vinitial = (nRT) / P = (8 * 8.314 * Tinitial) / 6
Substituting the known values, we get:
Vinitial = (8 * 8.314 * Tinitial) / 6 = 50 liters
Solving for Tinitial, we find that the initial temperature of the gas is approximately -217.6 degrees Celsius. Converting this temperature to Kelvins, we find that the initial temperature of the gas is 55.55 K.
Now that we know the initial and final temperatures of the gas, we can use the equation for isobaric heat capacity to calculate the heat that must be eliminated from the system:
q = Cpm * (Tfinal - Tinitial) = 22 * (123.15 - 55.55) = 22 * 67.6 = 1521.2 J
Therefore, the volume of the gas after compression is 205.7 liters, and the heat that must be eliminated from the system is 1521.2 J.
4. can the heat and pressure change the composition and appearance of the minerals in rocks?
Jawaban:
Different temperatures and pressures cause new minerals to grow in rocks that have the same composition.
5. A gas at 250K and 15atm has a molar volume 12% smaller than that calculated for the equation of state of an ideal gas. Hence calculate: The compressibility factor (Z) for this temp and pressure The molar volume of the gas
aku tidak tahu..........
6. Calculate the change in the internal energy of one mol of a monoatomic ideal gas when the temperature goes from 0°C to 50°C.
Jawaban:
Hitung perubahan energi dalam satu mol gas ideal monoatomik ketika suhunya berubah dari 0°C menjadi 50°C.
7. A mass of an ideal gas of volume v, at pressure p, undergoes a cycle of changes as shown in the graph.
Jawaban:
Sebuah massa gas ideal volume v, pada tekanan p, mengalami siklus perubahan seperti yang ditunjukkan pada grafik.
Penjelasan:
Translate:
A mass of an ideal gas of volume v, at pressure p, undergoes a cycle of changes as shown in the graph.
Sebuah massa gas ideal volume v, pada tekanan p, mengalami siklus perubahan seperti yang ditunjukkan pada grafik.
semoga membantu
8. Blood pressure measurement has two components: systolic and diastolic. Systolic pressure is taken when the heart is contracting to pump blood; diastolic pressure is taken when the heart is resting between beats. In the usual blood pressure reading, the systolic measurement is given first and is the higher of the two. Normal blood pressure is a systolic measurement of 120—140, and when the systolic pressure is 160 or higher, then hypertension exists. Systolic pressure between 140 and 160 indicates borderline hypertension.Which of the following is NOT stated about diastolic pressure?a.A diastolic measurement of 140 is normal.b.Ꝋc.It is lower than systolic pressure.d.It is taken when the heart is resting.e.It is one of the two components of blood pressure measurement.
Blood pressure measurement has two components: systolic and diastolic. Which of the following is NOT stated about diastolic pressure? A diastolic measurement of 140 is normal.
Pembahasan :A diastolic measurement of 140 is normal. Dari pernyataan tersebut bisa disimpulkan bahwa pernyataan itu bertentangan dari informasi yang telah dipaparkan pada teks baris ke 5 sampai 6.
Tekanan darah adalah kekuatan yang dibutuhkan darah untuk mengalir melalui pembuluh darah dan beredar di seluruh jaringan tubuh manusia. Tekanan darah manusia bukanlah nilai yang konstan, tetapi nilai yang berfluktuasi sepanjang hari. Perubahan ini umumnya dipengaruhi oleh beberapa faktor seperti aktivitas fisik, aktivitas mental, dosis, diet, dan lingkungan.
Tekanan darah terdiri dari tekanan darah sistolik dan diastolik. Tekanan darah diastolik dikaitkan dengan tekanan arteri saat jantung berelaksasi di antara detak jantung. Tekanan darah sistolik adalah tekanan darah saat jantung berkontraksi (sistolik). Tekanan darah diastolik adalah tekanan darah saat jantung berelaksasi. Regulasi tekanan tergantung pada curah jantung dan resistensi perifer total.
Peningkatan denyut jantung berpengaruh langsung terhadap tekanan darah sistolik, tetapi tekanan darah diastolik lebih dipengaruhi oleh resistensi perifer total sebesar , dengan rata-rata sistolik 100-140 mmHg dan rata-rata diastolik 60-90 mmHg. Tekanan darah pada wanita 5-10 mmHg lebih rendah dari pada pria. Tekanan darah normal adalah sekitar 120/80 mmHg. Jika tekanan darah Anda di bawah normal, itu dinilai sebagai hipotensi atau hipotensi. Tekanan darah manusia berfluktuasi naik turun dari masa-masa kejam sesuai kebutuhan. Pembuluh darah di leher (arteri karotis) memiliki pusat pengatur tekanan darah (reseptor boron) yang mengatur tekanan darah untuk naik saat turun dan turun saat naik. Pengaturan ini bekerja secara otomatis.
Pelajari Lebih LanjutMateri tentang Tekanan darah brainly.co.id/tugas/18811802Materi tentang Tekanan darah diastolik brainly.co.id/tugas/22911823Materi tentang Selisih tekanan darah diastolik dengan sistolik brainly.co.id/tugas/4970250Detail JawabanKelas : 11
Mapel : Seni Budaya
Bab : 5 - Sistem Peredaran Darah
Kode : 11.4.5
#AyoBelajar #SPJ2
9. According to Bernoulli's principle, the higher the speed of a fluid gas, ___ the pressure
Jawaban:
According to Bernoulli's principle, the higher the speed of a fluid gas, ___ the pressure
Penjelasan:
Getting lower
10. Concentration of 20 ml of H 2 SO4 is unknown, then titrated with NaOH 0.1 M solution using phenolphthalein indicator. When the NaOH volume is exactly 30.2 ml the color of the indicator starts to change. a. Determine the concentration of H 2 SO4. b. What do you think the pH of mixed solution when indicator starts to change?
Jawaban:
Data given :
Volume H₂SO₄ = 20 mL
Concentration of NaOH = 0,1 M
Final Volume of NaOH during titration = 30,2 mL
Question and answer :
1 Concentration of H₂SO₄
M₁V₁n₁ = M₂V₂n₂
M₁.20.2 = 0,1. 30,2. 1
M₁ = 0,0755 M
2. What do you think the pH of mixed solution when indicator starts to change?
pH when the mixed indicator starts to change is 7. Because the indicators mixed are strong acid and strong base. Based on the theory of hydrolysis, when we mix strong acid and strong base, their ions are not gonna be raveled in the water, so pH stand still at 7 ( neutral )
CMIIW.
11. When a 14.0 kg mass hangs from a spring that has a spring constant of 550 N/m, the spring has a length of 82 cm. Determine the length of the spring before any force is applied to it.
Penjelasan:
given :
m = 14.0kg
k = 550N/m
g= 10 m/s²
total length = 82cm = 0,82m
find:
the length of the spring before any force is applied to it, Lo =?
solutions:
F = m. g = 14.0 × 10 = 140N
F = k. ∆x
140 = 550.(0,82 -Lo)
14 = 55(0,82 -Lo)
14 = 45.1 - 55Lo
55Lo = 45.1 -14
= 31.1
Lo = 31.1/ 55
= 0.565m
= 56.5cm
12. Calculate the change in the molar Gibbs energy of water vapour (treated as a perfect gas) when the pressure is increased isothermally from 1.0 bar to 2.0 bar at 298 K. Note that, whereas the change in molar Gibbs energy for a condensed phase is a few joules per mole, the answer you should get for a gas is of the order of kilojoules per mole.
Jawaban:
inggris loh aku gak tau
13. When the frequency of a wave is increased, what happens to :A.) the wavelength if the speed is constant?B.) The speed of the wave if the Wavelength is constant? Mohon bantuannya, hari ini duenya
Penjelasan:
A. Wavelength = speed/frequency, so if frequency increased wavelength will decereased
B. Speed = wavelength. Frequency, so if frequency increased speed will increased
14. What is the effect of pressure and temperature toward the gas particles?
tekanan dan suhu menyebabkan jarak dan interaksi antar partikel gas berubah...
suhu tinggi membuat gerak antar pertikel menjadi lebih besar dan jarak antar partikel mnjadi lbih renggang, akhirnya volume gas membesar dan massajenisnya mengecil.
tekanan yg besar membuat jarak antar partikel menjadi lebih rapat
15. Blood pressure measurement has two components: systolic and diastolic. Systolic pressure is taken when the heart is contracting to pump blood; diastolic pressure is taken when the heart is resting between beats. In the usual blood pressure reading, the systolic measurement is given first and is the higher of the two. Normal blood pressure is a systolic measurement of 120—140, and when the systolic pressure is 160 or higher, then hypertension exists. Systolic pressure between 140 and 160 indicates borderline hypertension.Which of the following is NOT true about systolic blood pressure?a.It is taken during the contraction of the heart.b.It is usually given first in a blood pressure reading.c.Ꝋd.A normal systolic measurement is 120 – 140.e.Hypertension exists when the systolic pressure is below 140.
Jawaban:
e. Hypertension exists when the systolic pressure is below 140.
Penjelasan:
Yang ditanyakan adalah: Which of the following is NOT true about systolic blood pressure? (Dari bawah ini mana yang tidak benar mengenai tekanan darah sistolik?)
Maka jawabannya adalah E, karena pernyataan E salah. Pada teks dijelaskan bahwa "when the systolic pressure is 160 or higher, then hypertension exists.", yang berarti "ketika tekanan sistolik itu 160 keatas, maka ada hipertensi." sedangkan pernyataan tersebut adalah "Hypertension exists when the systolic pressure is below 140," yang berarti "Hipertensi ada ketika tekanan sistolik dibawah 140.".
16. A gas at 250 K has a pressure of 0.00008 Pa. If the pressure drops to 0.00002 Pa, what is the new temperature?
Jawaban:
If a gas at 250 K has a pressure of 0.00008 Pa and the pressure drops to 0.00002 Pa, 62.5 K is the new temperature
Explanation: -
Initial Pressure P₁ = 0.00008 Pa
Final Pressure P₂ = 0.00002 Pa
Initial Temperature T₁ = 250 K
Since the volume is not mentioned, it remains constant.
So initial Volume V₁ = Final volume V₂
Now using the combined gas equation
\frac{P1 V1}{T1}T1P1V1 = \frac{P2 V2}{T2}T2P2V2
Final Temperature T₂ = \frac{P 2 V2 T1}{P1 V1}P1V1P2V2T1
Plugging in the values,
T₂ = \frac{0.00002 Pa x V2 x 250 K}{0.00008 Pa x V1}0.00008PaxV10.00002PaxV2x250K
As V₂ = V₁, they cancel each other.
T₂ = 62.5 K
17. bantu pls thx .. question : use the particulate model of matter to explain whwhy there is a large volume change when a liquid boils to become a gas but only a small volume change when a liquid freezes to a solid
Gunakan peragaan tersebut untuk menjelaskan mengapa terjadi perubahan volume yg banyak ketika benda cair memanas menjadi gas, sedangkan hanya (terjadi) perubahan volume sedikit saat benda cair membeku menjadi benda padat.
18. determine the combined volume of the figure!please answer!!!!
Jawab:
Volume balok = p x l x t
= 40 cm x 35 cm x 15 cm
= 21.000 [tex]cm^{3}[/tex]
Volume prisma segitga = ([tex]\frac{a . t}{2}[/tex] x t. prisma)
= [tex]\frac{35 cm . 35}{2}[/tex] x 40 cm
= 612.5 x 40 cm
= 24.500
so the combined volume is 45.500 [tex]cm^{3}[/tex]
Penjelasan dengan langkah-langkah:
Semoga membantu yaa..
19. what is the effect of pressure, temperature toward the gas particles?
ketika terjadi perubahan temperatur dan tekanan udara, partikel udara juga terpengaruh, mulai dari pergerakan, massa jenis, dan sebagainya.
semoga bermanfaat..
20. Steam is contained in a closed rigid container with a volume of 1 m 3 . Initially, the pressure and temperature of the steam are 7 bar and 500 o C, respectively. The temperature drops as a result of heat transfer to the surroundings. Determine the temperature at which condensation first occurs, in o C, and the fraction of the total mass that has condensed when the pressure reaches 0,5 bar. What is the volume in m 3 , occupied by saturated liquid at the final state?
Jawaban:
minta contoh pengerjaannya dong kerna kurang ngerti
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