Solve the equation=2(3×)-5 1+x=0
1. Solve the equation=2(3×)-5 1+x=0
1 + x = 0
1 - 1 + x = 0 - 1
x = - 1
2 ( 3x ) - 5
2 ( 3(-1) ) - 5
2 ( -3 ) - 5
-6 - 5
= -11
1+x=0
x=-1
2 (3x) - 5 = 2 (3.(-1)) - 5
= - 6 - 5
= - 11
2. 1. Solve the equation |x + 2| = 62. Solve the equation |3x - 2| = 2x + 43. Solve |2x - 1| = |x + 4|tolong, Kak. ini harus sekarang
Jawaban:
1. |x+2|=6
x+2=6
x= 6-2
x= 4
x+2=-6
x= -6-2
x= -8
maka hp nya adalah x= -8; x= 4
2. |3x-2|= 2x+4
3x-2= 2x+4
3x-2x= 4+2
x= 6
3x-2= -2x-4
3x+2x= -4+2
5x= -2
x= -2/5
maka hp nya adalah x= -2/5; x=6
3. |2x-1|= |x+4|
2x-1= x+4
2x-x= 4+1
x=5
2x-1= -x-4
2x+x= -4+1
3x= -3
x= -3/3
x= -1
maka hp nya adalah x= -1; x=5
3. -1/x=7/2+2/x. Solve the equation
Jawab:
x =
Penjelasan dengan langkah-langkah:
-1/x = 7/2 + 2/x
-3/x = 7/2
1/x = -7/6
x = -⁶/ [tex] _7 [/tex]
4. Solve the equation. 1. x - 3 = 5 2. 2x + 6 = 10 3. 5x = 12 - x 4. 2x - 4 = x + 1 5. 7x + 12 = 36 + x
Jawaban:
x - 3 = 5
x = 5 + 3
x = 8
2x + 6 = 10
2x = 10 - 6
2x = 4
x = 4/2
x = 2
5x = 12 - x
5x + x = 12
6x = 12
x = 12/6
x = 2
2x - 4 = x + 1
2x - x = 1 + 4
x = 5
7x + 12 = 36 + x
7x - x = 36 - 12
6x = 24
x = 24/6
x = 4
5. solve the equation below x^2 = 3x + 2 = 0
Assume that the typo in the right side of x² is a pus (+) symbol.
So,
x² + 3x + 2 = 0
Factorize it.
(x+1)(x+2) = 0
Get some radixes:
x₁ + 1 = 0
x₁ = -1
x₂ + 2 = 0
x₂ = -2
So, the solution of the equations are:
x = {-2,-1}
[tex]\displaystyle x^2+3x+2=0\\x^2+2x+x+2=0\\x(x+2)+1(x+2)=0\\(x+1)(x+2)=0\\\\x+1=0\\x=-1\\\\\text{or}\\\\x+2=0\\x=-2\\\\\boxed{\boxed{S=\{-1,-2\}}}[/tex]
6. 1.Ekspresi |-x2 + 1 | untuk -1≤ x ≤ 3 mempunyai nilai terkecil yaitu ... 2.Solve the following equation: |2x - 3| = 3 3.Solve the following equation: |x +1| = |2x-3|
Jawaban:
maaf cuma jawab no satu
Penjelasan dengan langkah-langkah:
jika mau bertanya lebih lanjut DM IG KITA @barbarboos
7. solve the equation below 3 - 2x - x^2 = 0
Use some tricks.
[tex]$\begin{align}3-2x-x^2&=0 \\ \text{Multipty both }& \text{sides by (-1)} \\ (-1)(3-2x-x^2)&=(-1)(0) \\ -3+2x+x^2&=0 \\ x^2+2x-3&=0 \\ (x+3)(x-1)&=0\end{align}[/tex]
The correct x are:
x = {-3,1}
[tex]x^2-x+3x-3=0 \\ \\ x(\frac{x^2}{x}-{x}{x}+3(\frac{3x}{3}-\frac{3}{3})=0 \\ \\ x(x^{2-1}-1)+3(x-1)=0 \\ \\ (x-1)(x+3)=0 \\ \\ \\ x-1=0 \\ \\ x+3=0 \\ \\ x=1 \ dan \ x=3 \\ \\[/tex]
Jadi x∈{1,-3}
8. Solve for x: |x-5|=2|x+1|
(x-5 +2x+2)(x-5 - (2x+2)) = 0
(3x - 3) (-x+3) = 0
x = 1 atau x = 3
9. solve equation (x-3)^2-1=0
Jawab:
=
4
=
2
Penjelasan dengan langkah-langkah: [ x3 [ x3 −
1
=
0
{\col
10. 8. Solve the equation3^(5x + 2) / 9^(1 - x) = 27^(4 + 3x) / 729
Penjelasan dengan langkah-langkah:
Silahkan di klik gambarnya
11. Solve the equation 2π - x² = 0
Penjelasan dengan langkah-langkah:
penjelasan terlampir di foto
12. Form an equation in x use it to solve for X
4 · 15 = x + 10 + x + 8 + 28
60 = 2x + 46
14 = 2x
x = 7
Sekian,semoga membantu.(x + 10 + x + 8 + 28) / 4 = 15
2x + 46 = 15 × 4
2x = 60 - 46
x = 14/2
x = 7
Kalau boleh jadikan jawaban terbaik yah.
13. given the functions f(x) = x^2 - x and g(x) = x^2 - 3x - 12 a. solve the equation f(x) = 6 b. solve the equation f(x) = g(x)
Jawaban:
BSOLVETHEEQUATIONF(X)=6Penjelasan dengan langkah-langkah:
MAAFKALAUSALAH14. Solve the exponential equation for
Jawaban:
x= -4
Penjelasan dengan langkah-langkah:
Itu 1 saat:
(9/8)⁰
3x+12= 0
3x= -12
x= -4
[tex]( \frac{9}{8} ) {}^{3x + 12} = 1 \\ ( \frac{9}{8} ) {}^{3x + 12} = ( \frac{9}{8} ) {}^{0} \\ 3x + 12 = 0 \\ 3x = - 12 \\ x = \frac{ - 12}{3} \\ x = - 4[/tex]
[tex] \: [/tex]
»Detail Jawaban: Mapel: Matematika Kelas: X Materi: Eksponensial#AyoBelajar!
15. Form an equation in x use it to solve for X
(x + 10 + (x+8) + 28) / 4 = 15
2x + 46 = 15 . 4
2x = 60 - 46
2x = 14
x = 7
(x + 10 + x + 8 + 28) / 4 = 15
2x + 46 = 15 × 4
2x = 60 - 46
x = 14/2
x = 7
Kalau boleh jadikan jawaban terbaik yah.
16. 2(x-1)+3(x+1)=4(x+4) Solve the equation tolong jawab dengan caranya ya yang lengkap
Jawaban:
(2(x-1)) + (3(x+1)) = 4(x+4)
2x - 2 + 3x + 3 = 4x + 16
5x + 1 = 4x + 16
5x - 4x = 16 - 1
x =15
17. 2(x-1)+3(x+1)=4(x+4) Solve the Equation
Jawaban:
2x-2+3x+3=4x+16 ( dikali masuk ke dalam kurung)
5x+1=4x+16 ( pindahkan variabel dengan variabel dan konstanta dengan konstanta)
x=15
18. solve the equation:[tex]2( {3}^{x} ) - {5}^{x + 1} = 0[/tex]
Jawaban:
maaf ka klo salah, trima kasih
19. Pls solve the equation, thank you! (x+1)(x-2)(x-3)>=0
Pertidaksamaan
(x + 1)(x - 2)(x - 3) ≥ 0
Pembuat nol
x + 1 = 0 ---> x = -1
x = 2
x = 3
- - ...(-1) ... ++ ... (2) ... - - ... (3) ... ++
Nilai x yg memenuhi :
-1 ≤ x ≤ 2 atau x ≥ 3jawab
(x+1) ( x-2)(x - 3) ≥ 0
x = - 1 , x = 2, x = 3
garis bilangan
.. (-)...(-1)...(+)..(2)..(-)...(3)..(+)..
daerah HP ≥ 0 (daerah (+) )
Hp -1 ≤ x ≤ 2 atau x ≥ 3
20. 9 Given the functions f(x)= x² - x and g(x)= x² – 3x – 12,asolve the equation f(x) = 6b solve the equation f(x) = g(x).
Penjelasan dengan langkah-langkah:
a.) f(x)=6
=>6=x²-x
x² - x - 6 = 0
(x + 2) (x - 3) = 0
x = -2, and x = 3
b.) f(x) = g(x)
g(x) = 6
=>6=x²-3x-12
=> x² - 3x - 12 - 6
=> x² -3x - 18
(x - 6) (x + 3) = 0
=> x=6,andx=-3
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