. In RP A of Dentistry, Airlangga University there were pieces of Arsenate element. A student once tried to react between Oxygen and Arsenate in acidic condition and he observed what substance would be produced. In the end of the experiment, he found molecules of Hydrogen Arsenate (HAsO2) and water. O2 + As ---> HAsO2 + H2O. Determine how many As he used! (A)3 mole (B) 2 mole (C) 8 mole (D)4 mole (E) 6 mole
1. . In RP A of Dentistry, Airlangga University there were pieces of Arsenate element. A student once tried to react between Oxygen and Arsenate in acidic condition and he observed what substance would be produced. In the end of the experiment, he found molecules of Hydrogen Arsenate (HAsO2) and water. O2 + As ---> HAsO2 + H2O. Determine how many As he used! (A)3 mole (B) 2 mole (C) 8 mole (D)4 mole (E) 6 mole
If want to know how many As is used in the reaction. We have to balance the reaction between O2 and As. Based on the reaction all of the elements lead to oxidation and reduction. We have to find out of each elements whether either oxidation or reduction.
Based on the reaction the O2 leads to reduction. So, we can write an equation reaction of the O2.
O2 → H2O
The As leads to reduction. So, we can write the reaction of As.
As → HAsO2
By using half-reaction method. We can balance redox reaction.
Red : O2 + 4H+ + 4e → 2H2O | x 3
Oks : As + 2H2O → HAsO2 + 3H+ 3e | 4
To make the two equal, multiply the coefficients of all species by integers producing the lowest common multiple between the half-reactions.
4As + 3O2 + 8H2O + 12H+ + 12e- → 4HAsO2 + 6H2O + 12H+ + 12e-
Simplify the equation. The same species on opposite sides of the arrow can be canceled.
So, we can write the balance of whole coefficients reaction
4As + 3O2 + 2H2O → 4HAsO2
Based on the reaction. We know that there are 4 coefficient of As, So, in the reaction between O2 and As. It needs 4 mole of As to completely the reaction.
Wish it hepled
Keep Learning
Footnote :
periodni.com/half-reaction_method/
@XeMore
2. The heat of combustion of ethane gas is 373 kcal/mole. Assuming that б0.0 percent of the heat is useful, how many liters of ethane, measured at standard temperature and pressure, must be burned to convert 50.0 kg of water at 10.0 ° C to steam at 100.0 °C? One mole of a gas occupies 22.4 liters at precisely 0 °C and 1 atm.
Jawaban:
3143.28 liters of ethane gas must be burned .
Penjelasan:
m = 50 kg
η = 60%
c = 4200 J/kg°C
L = 2.260.000 J/kg
Kalor Untuk memanaskan air dari 10 °C menjadi 100 °C
Q₁ = m.c.ΔT
Kalor Untuk menguapkan air dari 100 °C menjadi uap 100 °C
Q₂ = m. L
Kalor Untuk memanaskan air dari 10 °C menjadi uap 100 °C
Q = Q₁ + Q₂
Q = m.c.ΔT + m. L
Q = 50. 4200. (100 - 10) + 50. 2.260.000
Q = 131900000 J
Q ini merupakan 60% dari kalor pembakaran gas etana awal.
Kalor pembakaran gas etana awal
Qa = 100/60 . 131900000
Qa = 219833333,3 J
Panas pembakaran gas etana 373 kcal/mole
= 373000 cal/mole
=373000 . 4,2 J/mole
= 1566600 J/mole
Jumlah mol gas etana yg dibakar n
n = 219833333,3/1566600 = 140,325 mol
Jumlah liter gas etana = n . 22,4 l
= 140,325 . 22,4
= 3143.28 liters
3. 100.0-g sample of a brand of rubbing alcohol contrains 65,0g of isopropyl alcohol C3 H7 OH and 35,0g of water. Whats is the mole fraction of isopropyl alcohol in the solution? What is the mole fraction of water?
Semoga dapat membantu ^^
4. 15. At temperature 63.5 °C, the vapour pressures of pure H20 and pure ethanol, C2H5OH,are 175 and 4.00 x 102 torr, respectively. A solution is prepared by mixing equal masses ofH2O and C2H5OH.a) Calculate the mole fraction of ethanol in the solution.b) What is the vapour pressure of the solution at 63.5 °C?c) Determine the mole fraction of ethanol in the vapour phase above the solution.
Jawaban:
SELAM
Penjelasan:
Soru basitti
Cevap
merıpbdvre m
BAŞARILAR
5. What do you know about the phrase "the day after tomorrow" in indonesia equivalents?
Jawaban:
What do you know about the phrase "the day after tomorrow" in Indonesia equivalents?
The day after tomorrow means lusa in Indonesia equivalents. Or the day after tomorrow in Indonesia equivalents lusa.
Penjelasan:
Arti dari pertanyaan di atas adalah "Apa yang Anda ketahui tentang frasa "the day after tomorrow" dalam padanan bahasa Indonesia?
Arti dari the day after tomorrow adalah hari setelah besok, yang dalam bahasa Indonesia disebut dengan lusa.
Lusa yaitu hari sesudah besok; hari yang ketiga sesudah hari ini
Pelajari lebih lanjut names of days in a week pada https://brainly.co.id/tugas/1229667
#BelajarBersamaBrainly
6. Cobalt is a metallic element. One of the compounds of cobalt is vitamin B12, which has the formula C⁶³H⁸⁸CON¹⁴0¹⁴P. Another compound of cobalt is cobalt (II) chloride, which has the formula CoCl². Vitamin B12 is a molecule, whereas cobalt (II) chloride is not molecule. Which of the following statements is/are true?1. The bond formed by the metallic element to the rest of the molecule in Vitamin B12 is ionic.2. There are 6 elements found in vitamin B12, whereas there are only 2 elements in cobalt (II) chloride.3. One mole of vitamin B12 contains 60 times the number of particles in one mole of cobalt (II) chloride.4. There are 181 atoms in a molecule of vitamin B12, whereas there are only 3 atoms in the ionic formula of cobalt (II) chloride.A) option 1 onlyB) option 1 and option 3C) option 2 and option 4D) all optionsMy guess is C, because molecules are formed from covalent instead of ionic bonds. Can anyone clarify?Thank you!
Jadi jawaban yang sesuai adalah C. opsi 2 dan opsi 4.
PembahasanIkatan antara unsur logam Co dengan molekul Vit B-12 bukanlah ikatan ionik, melainkan ikatan kovalen karena terdapat pasangan elektron bersama di dalamnya. Kalau dilihat akan kompleks sebenarnya. Kalau CoCl₂ kan termasuk senyawa ionik, yang terbentuk atas unsur logam dan unsur non logam, jelas ikatan terjadi karena interaksi ionik (beda elektronegativitas yang tinggi) jadi bisa dikatan terbentuk oleh ikatan ionik.Pengertian senyawa molekul dan senyawa ionik ==> tidak sesederhana senyawa biner saja ya :D.Ada 6 jenis unsur dalam Vit B-12 jelas :
C = karbon
H = hidrogen
Co = cobalt
N = nitrogen
O = oksigen
P = fosforSesuai dengan bilangan avogadro ya,
Satu mol senyawa/unsur/molekul akan memiliki jumlah partikel yang sama dengan bilangan avogadro.
Jadi : jumlah partikel dari 1 mol Vit B-12 = jumlah partikel dari 1 mol cobalt (II) klorida.Jumlah atom = 63+88+1+14+14+1 = 181 atoms
Oke cocok ya. Angka itu adalah jumlah atom masing-masing unsur sesuai rumus molekul yang kamu berikan.
----------------------------------------------------------------------------------------------------
Pelajari lebih lanjutMateri tentang bilangan avogadro :brainly.co.id/tugas/9979067Materi tentang hukum dasar kimia :
brainly.co.id/tugas/22667817Materi tentang cara menghitung jumlah partikel : brainly.co.id/tugas/178366
----------------------------------------------------------------------------------------------------
Detail jawabanMapel : Kimia
Kelas : X
Bab : Hukum Dasar Kimia
Kode : 10.7.6
----------------------------------------------------------------------------------------------------
7. The mole fraction of solute and solvent if 15 gram of acetic acid (CH3COOH) is dissolved in 90 gram of water is
solute: acetic acid (CH₃COOH, Mr = 60)
solvent: water (H₂O, Mr = 18)
mole of solute: mass / Mr = 15 gr / 60 = 0,25
mole of solvent: mass / Mr = 90 gr / 18 = 5
X solute = moles of solute / total moles of solution
X solute = 0,25 / (0,25 + 5)
X solute = 0,0476
X solvent = 1 - X solue
X solvent = 1 - 0,0476
X solvent = 0,9524
8. Berapa Energi Kinetik Translasi dari satu mole suatu Gas Ideal pada suhu 0°C
Jawaban:
Dalam artikel ini akan membahas tentang teori kinetik gas secara keseluruhan, mulai dari pengertian gas ideal, persamamaan umum gas ideal, persamaan keadaan gas ideal, tekanan gas ideal, energi kinetik gas ideal, dan energi dalam gas ideal. Yuk, simak pembahasan lengkap tentang teori kinetik gas di bawah ini!
9. the mole fraction of solute and solvent if 15 gram of acetic acid (ch3cooh) is dissolved in 90 gram of water is
i dunno how to speak chemistry with English but I'll try to answer in Bahasa.
Diketahui :
nt =15 gram
np= 90 gram
Ditanya : Xp and Xt?
Penyelesaian :
Xp = np/np+nt = 90/90+15 = 0,85714286
Xp + Xt = 1
Xt = 1 - 0,85714286 = 0,14285714
10. 3.0 g of magnesium was added to 12.0g of ethanoic acid. Mg + 2CH 3 COOH → (CH3COO)2Mg + H 2 The mass of one mole of Mg is 24g. The mass of one mole of CH3COOH is 60g. Which one, magnesium or ethanoic acid, is in excess? You must show you nasoning
mass of Mg = 3 g
Atomic relative Mg (Ar) = 24 g/mole
mass of CH3COOH = 12 g
Molecular relative of CH3COOH (Mr) = 60 g/mole
Reaction occurs:
Mg + 2CH3COOH → (CH3COO)2Mg + H2 (balance)
first, calculate mole for each reactant[tex]n \: = \frac{mass}{Ar/Mr} [/tex]
[tex]n \: Mg= \frac{3 \: g}{24 \: g/mole} = 0.125 \: mole [/tex]
[tex]n \: CH _{3}COOH = \frac{12 \: g}{60 \: g/mole} = 0.2 \: mole [/tex]
identifying the limiting reactant from balanced equation, use the mole from calculation before and use coefficient for each reactant from balanced equation[tex]limiting \: reactant = \frac{mole \: reactant}{coefficient \: of \: reactant} [/tex]
[tex]limiting \: Mg = \frac{0.125}{1} = 0.125 \: mole[/tex]
[tex]limiting \: CH_{3}COOH = \frac{0.2}{2} = 0.1 \: mole[/tex]
use CH3COOH as limiting reactant because it has smallest mole quantity, so for 1 coefficient of each compoundcompound is 0,1 mole.
calculate the remaining reactantMg + 2CH3COOH → (CH3COO)2Mg + H2
initial 0.125 0.2 - -
reacted 0.1 0.2 0.1 0.1
excess 0.025 - 0.1 0.1
calculate mass of excess reactant, Mg[tex]mass \: = excess \: mole \: \times Ar = 0.025 \: mole \times 24 \: g/mole = 0.6 \: g[/tex]
11. A 1.000 mol sample of propane, a gas used for cooking in many rural areas, was placed in a bomb calorimeter with excess oxygen and ignited. The initial temperature of the calorimeter was 25.000 °C and its total heat capacity was 97.13 kJ °C-1. The reaction raised the temperature of the calorimeter to 27.282 °C. (a) Write the balanced chemical equation for the reaction in the calorimeter. (b) How many joules were liberated in this reaction? (c) What is the heat of reaction of propane with oxygen expressed in kilojoules per mole of C3H8 burned?
Kimia Kelas XI
Termokimia
Mohon koreksinya ya! Semoga membantu :) Tetap semangatt ^^
12. the mole fraction of solute and solvent if 15 gram of accetic acid (CH3COOH)is dissolved in 90 gram of water is
nt = massa terlarut/mr terlarut
nt = 15/60
nt = 0,25 mol
np = massa pelarut/mr pelarut
np = 90/18
np = 5 mol
fraksi mol pelarut
xp = np/nt+np
xp = 5/5+0,25
xp = 0,9524
fraksi mol terlarut
xt = 1-xp
xt = 1-0,9524
xt = 0,0476solute 0.05 dan solvent 0.95
13. Is-the-dug-the ground-mole-out of-usually
The mole is usually dug out of the ground.
___________
#Semoga bermanfaat ^_^Answer:
The mole is usually dug out of the ground
Thanks
14. Which of thefollowing correctly defines lattice energy? AIt is the energy required to convert a mole of ionic solid into its constituent ions in the gas phase.BIt is the energy given off when gaseous ions combine to form one mole of an ionic solid.CIt is the energy required to produce one mole of an ionic compound from its constituent elements in their standard states.DIt is the sum of ionisation energies of the components in an ionic solid. Kenapa A bukan B
Jawaban:
What affects lattice energy?
This model emphasizes two main factors that contribute to the lattice energy of an ionic solid: the charge on the ions, and the radius, or size, of the ions.
Penjelasan:
The effect of those factors is: as the charge of the ions increases, the lattice energy increases.
15. Determine the mole fraction of solute and solvent if 15 gra of acetic acid (CH3COOH) is dissolved in 90 gram of water
n acetic acid= m/Mr= 15/60=0,25
n water = m/Mr= 90/18=5
Solute fraction = 0,25/(0,25+5)= 0,25/5,25
Solvent fraction = 5/(0,25+5) = 5/5,25
16. determine the mole fraction of solute and solvent if 15 gram of acetic acid (CH3COOH) is dissolved in 90 gram of water?
n CH₃COOH = gr/Mr = 15/60 = 0,25 mol
n H₂O = gr/Mr = 90/18 = 5 mol
n solution = 0,25 + 5 = 5,25 mol
mole fraction of solute
[tex]Xt= \frac{n~CH_3COOH}{n~solution} \\ \\ = \frac{0,25}{5,25}=0,048 [/tex]
mole fraction of solvent
1-0,048 = 0,952
17. change the following passive sentences into their active equivalents!! 1. much more energy is sent into the ruby crystal by the flash lamp. 2. these atoms are struck by the oscillating electrons in the tube and get exited. 3. if the source emits a broad band of wavelengths, a broad band of color will be seen. 4. we are surrounded by many every day cases of oscillations. 5. absorption spectra are found when the light from stars is analyzed.
1. The first lamp sends much more energy into the ruby crystal.
2. Oscillating electrons in the tube strike these atoms (and get excited
merupakan ungkapan yang janggal karena tidak "agreement" alias
selaras dengan bentuk passive)
3. (soalnya kurang teliti, karena subjek atau pelaku tidak ada, maka
diumpakan pelakunya adalah we/you) if the source emits a broad band
of wavelengths, you will see a broad band of color.
4. Many everyday cases of oscillations surround us.
5. (ini hampir sama kasusnya dengan no. 3, maka diadakanlah pelaku)
You find absorption spectra when the light from stars is analyzed.
18. 4.20. A 100 kmol/h stream that is 97 mole% carbon tetrachloride (CCl) and 3% carbon disulfide (CS) is to be recovered from the bottom of a distillation column. The feed to the column is 16 mole% CS, and 84% CCL, and 2% of the CCl, entering the column is contained in the overhead stream leaving the top of the column. (a) Draw and label a flowchart of the process and do the degree-of-freedom analysis. (b) Calculate the mass and mole fractions of CCl, in the overhead stream, and determine the molar flow rates of CCI, and CS, in the overhead and feed streams. (c) Suppose the overhead stream is analyzed and the mole fraction of CS, is found to be significantly lower than the value caleulated in Part (b). List as many reasons as you can for the discrepancy including possible violations of assumptions made in Part (b).
Penjelasan:
Sebuah aliran 100 kmol/h yaitu 97 mol % karbon tetrachloride (CCl) dan 3% karbon disulfida (c) harus ditemukan dari dasar kolom penyulingan. Pakan ke kolom adalah 16 mol % c, dan 84% cc, dan 2% dari CCL, memasuki kolom terkandung dalam overhead stream meninggalkan bagian atas kolom. (a) gambarlah dan beri label diagram tentang proses dan buatlah analisis tingkat kebebasan. (b) hitung fraksi massa dan mole dari CCl, di aliran yang overhead, dan menentukan kecepatan aliran molar di CCI, dan c, di overhead dan aliran makanan. (c) misalkan aliran overhead yang dianalisis dan fraksi c, ditemukan secara signifikan lebih rendah daripada nilai yang didigangkan di bagian (b). Daftarkan sebanyak mungkin alasan untuk ketidaksesuaian termasuk kemungkinan pelanggaran asumsi dibuat di bagian (b)
minta nomor wa nya kak
saya kirim gambarnya
19. SOLVE THIS ??! Pure propane (C3H8) from El Paso is dehydrogenated catalytically in a continuous process to obtain propylene (C3H6). All of the hydrogen formed is separated from the reactor exit gas with no loss of hydrocarbon. The hydrocarbon mixture is then fractionated to give a product stream containing 88 mole % propylene and 12 mole % propane. The other stream, which is 70 mole % propane and 30 mole % propylene, is recycled. The one-pass conversion in the reactor is 25%, and 1000 kg of fresh propane are fed per hour. Find (a) the kg of product stream per hour, and (b) the kg of recycle stream per hour.
product stream per hour
20. Whac-A-Mole is a popular arcade game in-vented in 1976 by Aaron Fechter of Creative Engineering, Inc. In Japan, Mole Buster, a simi-lar game, ...... a year before Whac-A-Mole by Kazuo Yamada. (A) invented (B) which invented (C) was invented (D) which was invented
D. Which was invented
menunjukkan kalimat penjelas (defining clause)
0 komentar:
Posting Komentar