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What Is The Acceleration Of The 2 0 Kg Block

Posted by Serambi Pengetahuan on Rabu, 25 Mei 2022


What Is The Acceleration Of The 2 0 Kg Block

what is the definition of acceleration

Daftar Isi

1. what is the definition of acceleration


it means to increase in the rate or speed of something.

2. The volume of the block is 1,920cm3 what is the surafce area of the block


Sorry if wrong bro .

3. what is the resultant force and the acceleration of the object?​


Jawaban:

F=3+2-1=4N

[tex]a=\frac{F}{m}\\ a=\frac{4}{4} =1m/s[/tex]²

                   

Penjelasan:

resultan gaya

R = 3 + 2 - 1

R = 5 - 1

R = 4N

percepatan

f = m.a

4 = 4.a

a = 4/4

a = 1m/s


4. The mass of an object located on Earth is 120 kg. If the Earth’s gravitational acceleration is 9.8 N/kg and the moon’s gravitational acceleration is 1/6 of the Earth’s, then the weight of the same object on the moon is .. Mohon dibantu kak menggunakan cara.. Terima kasih


Dik : Massa Objek yang ada di bumi adalah = 120 kg
       Jika Gravitasi Bumi adalah 9.8 N/kg
       Dan Gravitasi Bulan = 1/6
Maka Ditanya : Berat Benda yang ada di bulan = ___? 
W di bulan = W di Bumi
=1/6 x m x g
=1/6 x 120 x 9.8
= 196 Newton

5. A planet has a mass of 7 times of the earth's mass and its radius is 3 Times of the radius of the earth's if the acceleration of gravity of the earth's surface is g; the acceleration of gravity of the planet is


diket: Mx = 7 Mb
Rx = 3 Rb
gb = g
ditanya: gx ...?
jawab: gx
gx/gb = Mx . Rb²/Mb . Rx²
gx/g = 7 Mb . Rb²/Mb . (3 Rb)²
gx/g = 7 Mb . Rb²/Mb . 9 Rb²
gx = 7/9 g

6. The rectangular block is 50 cm long. Two cubes, each of the volume 343 cm3 are cut from the ends of the rectangular block. what is the length of the remaining block?


Soal dapat diterjemahkan menjadi :

Balok segi empat memiliki panjang 50 cm. Dua kubus, masing-masing dengan volume 343 cm³ dipotong dari ujung balok persegi panjang, maka  panjang balok yang tersisa adalah 36 cm

Diketahui :

Balok

[tex]p[/tex] = 50 cm

Kubus (2 buah)

[tex]\text V[/tex] = 343 cm³

Ditanyakan :

Panjang balok yang tersisa

Jawab :

Satu buah kubus memiliki volume 343 cm³, maka volume kubus :

[tex]\text V_\text {kubus}[/tex] = s³

⇔ [tex]343[/tex] = s³

⇔ s =  [tex]\sqrt[3]{343}[/tex]

⇔ s =  [tex]7[/tex] cm

Panjang rusuk kubusnya adalah 7 cm

Banyak kubus adalah 2 buah, maka panjang balok yang tersisa adalah :

= panjang balok - panjang rusuk kubus 1 - panjang rusuk kubus 2

= 50 - 7 - 7

= 36 cm

∴ Jadi panjang balok yang tersisa adalah 36 cm


7. A car is pulled by a truck with an acceleration of 2 m/s2. If the mass of the car is 600 kg, then the force required to pull the truck is…


Jawaban:

F = 1.200 N

Penjelasan:

a = 2 m/s²

m = 600 kg

F = ... ?

F = m x a

F = 600 x 2

F = 1.200 N


8. 10N → 30N If the mass of cart is 20 kg, find the acceleration of cart! (jika massa kereta ada 20 kg, tentukanlah percepatan kereta)


Jawaban:

40:20=2km/j. ok paham


9. If the mass of the box = 4 kg, F1 = 10 N, and F2 = 2 N, then the magnitude and direction of the acceleration of the box is


Jawaban:

Magnitude: 4 m/s² Direction: towards the left (due to F1 being greater than F2)

Answer:

Acceleration of the box is 8 N.

Solution:

The magnitude and direction of the acceleration of the box can be calculated using Newton's Second Law, which states that the net force (Fnet) acting on an object is equal to the mass of the object (m) multiplied by its acceleration (a):

Fnet = ma

In this problem, the mass of the box is given as 4 kg. The forces F1 and F2 are given as 10 N and 2 N, respectively. Therefore, the net force is Fnet = 10 N - 2 N = 8 N.

Substituting the given values into Newton's Second Law, we have:

Fnet = ma

8 N = (4 kg)(a)

Solving for a, we have:

a = 8 N / (4 kg) = 2 m/s2

Therefore, the magnitude of the acceleration of the box is 2 m/s2 and the direction of the acceleration is in the same direction as the net force, which is 8 N.


10. 1. For each of the following problems, give the net force on the block, and the acceleration, including units. 2. The distance is measured from the point where the force is acting to the ….. bantu ya kakk plisssss


Jawaban:

maaf kurang ngerti karna cuman ambil coin


11. A student conducts an experiment to determine the acceleration of a trolley He measures the velocity of the trolley. At one instant , the velocity if the trolley is 1.0 m/s. Two seconds later, the velocity is 5.0 m/s. What is the acceleration of the trolley?


Jawaban:

2,0 m/s per detik

Penjelasan:

maaf kalau salah

Jawaban:

4m/s

Penjelasan:

• Acceleration of the trolley is 4 meter / s

#I'm sorry if I'm wrong


12. A student is investigating the pressure that a block of wood is exerting on the floor. The weight of the wood is 20 N. The block is 10 cm long, 5 cm wide, and 2 cm high. a What is the biggest pressure that the block can exert on the floor? b What is the smallest pressure that the block can exert on the floor?


Jawaban:
a. 200 Pa ( Pascal )
b. 40 Pa ( Pascal )

Penjelasan: Well, because the question asked for maximum and minimum pressure,
then we have to find the area of ​​the largest and smallest contact area, on a wooden block there are three variations of the area of ​​​​the touch area as follows:

Area Of Touch 1 :
→ A¹ = L x W = 10 x 5 = 50cm = 0,5 m

Area Of Touch 2 :
→ A² = L x h = 10 x 2 = 20cm = 0,2m

Area of touch 3 :
→ A³ = W X h = 5 x 2 = 10cm = 0,1 m

Of the three variations of the touch area above, the largest and smallest touch areas are A¹ and A²


Then the maximum pressure is:
→ Pmax = F/A³ = (w x g)/A³
Pmax = 20/0,1 = 200

Then the minimum pressure is:
→ Pmin = F/A¹ = (w x g)/A¹
Pmin = 20/0,5 = 40




I hope this helps (•‿•)



13. what is its acceleration at the highest point?


Jawaban:

apa itu akselerasi pada titik tertinggi


14. 3. A block of mass m/ = 4.0 kg is put on top of a block of mass m2 = 5.0 kg. To cause the top block to slip on the bottom one while the bottom one is held fixed, a horizontal force of at least 12 N must be applied to the top block. The blocks assembly is now placed on a horizontal, frictionless table, as shown in FIGURE 1. Find the magnitudes of a.the maximum horizontal force that can be applied to the lower block so that the blocks will move together b.the resulting acceleration of the blocks.


The maximum horizontal force that can be applied to the lower block is 5 N.The resulting acceleration of the blocks are 21,1 m/s².

Penjelasan dengan langkah-langkah:

Diketahui:

Massa 1 = 4 kg

Berat 1 = 40 N

Massa 2 = 5 kg

Berat 2 = 50 N

F1 = 12 N

Ditanya:

Gaya pada blok paling bawah (F2)?Percepatan (a)?

Jawab:

∑Fy1 = 0

N1 - W cos θ = 0

12 - 120 cos θ = 0

12 = 120 c0s θ

cos θ = 0,1

∑Fx1 = m1 x a

120 - T = 4a....(1)

∑Fy2 = 0

N2 - w cos θ = 0

N2 = w cos θ

N2 = 50 (0,1) = 5 N

∑Fx2 = m2 x a

50 sin θ + T = 5a

50 x 1 + T = 5a

50 + T = 5a..........(2)

120 - T = 4a

50 + T = 5a

___________ +

190 = 9a

a = 21,1 m/s²

from that calculation, we know that:

The maximum horizontal force that can be applied to the lower block is 5 N.The resulting acceleration of the blocks are 21,1 m/s².

Pelajari lebih lanjut

Materi tentang bidang miring pada link https://brainly.co.id/tugas/5259460

#BelajarBersamaBrainly

#SPJ1


15. An elevator with a mass of 2000 kg rises with an acceleration of 1.0 m/s/s. What is the tension in the supporting cable?​


Jawaban:

T - W = ma

W = mg

T = m(g + a)

Asumsikan g = 10 m/s^2

T = 2000(10 + 1)

T = 22000N

Penjelasan:

maaf kalo salah

Jawaban:

22000 newton

Penjelasan:

m = 2000kg

a = 1 m/s²

g = 10 m/s²

berat elevator terhadap bumi = m x g = 20000 Newton

tegangan yang ditimbulkan harus melebihi berat elevator terhadap bumi

dengan kata lain percepatan yang dihasilkan harus lebih besar dari percepatan gravitasi

sehingga percepatan sebenarnya tanpa pengaruh gravitasi = g + a = 10 + 1 = 11 m/s²

Tegangan yang dihasilkan = m x 11 = 2000 x 11 = 22000 newton


16. 1. What is the farmer's hat like? Answer: 2. What is the shape of a clock? Answer: 3. What is the blackboard like? Answer: 4. What is the shape of a pyramid? Answer: 5. What is the shape of an ice block? Answer:​


Jawaban:

1. Cone-shaped

2. Cylinder-shaped

3. Rectangular-shaped

4. Pyramid-shaped

5. Cube-shaped

Penjelasan:


17. The acceleration of a particle is inversely proportional to the square of the time since it was fired.If the acceleration of the particle 15 seconds after it was fired was 5 m/sec2, what was its acceleration 10 seconds later?


Jawaban:

3,3m/sec²

Penjelasan:

maybe ¯\_(ツ)_/¯ᵐᵃʸᵇᵉ


18. A stone is dropped from a height of 5 metres. What is the speed of the stone just before the stone reaches the floor? [gravitational acceleration = 10ms-²]​


Jawaban:

see the answer in the image attached. thanks

Penjelasan:


19. A rectangular block is 24 cm long. A cube with a volume of 216 cm3 is cut from the block. What is the volume of the remaining block?


V.cube = s³

s = √V.cube

s = √216

s = 6cm

[tex] \: \: [/tex]

V = V.rectangular - V.cube

V = (p × s²) - 216

V = (24 × 6²) - 216

V = 864 - 216

V = 648cm³

Jawaban:

648 cm³

penjelasan ada di foto yaa, maaf kalo kurang jelas

kalo ada yang salah bantu dikoreksi :))


20. A train of mass 800 000 kg is slowing down. What acceleration is produced if the braking force is 1 400 000 N


From task
we know :
mass = m = 800.000 kg
F = 1.400.000 N

Problem : acceleration?

solved :
a = F / m
   = 1.400.000 / 800.000
   = 1,75 m/s²

Video Terkait Topik Diatas


Thanks for reading & sharing Serambi Pengetahuan

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